How to Calculate an Empirical Formula from Percentage? Given: Find: Assume Mass % Use Grams of each element 100-g sample Empirical formula Calculate mole ratio Moles of each element elements molar mass 3. 4. A molecule containing only nitrogen and oxygen contains (by mass) 36.8% N. a) How many grams of N would be found in a 100 g sample of the compound? 100g x 36.8 = 36.89N How many grams of O would be found in the same sample? L03.290 100S-30.89 = lo3.2g0 b) How many moles of N would be found in a 100 g sample of the compound? Imol NatoYS 36.89+DO l679 = Z,663 mol Natoms 14,00679 g N atoms How many moles of O would be found in the same sample? 63.29) Imol D atoms 15.99949 O atoms = 3.95 mor O atorrs c) What is the ratio of the number of moles of O to the number of moles of N? =1.5=12 =30 2 N 3.95 Datoms %3D 11 2.663 N atoms d) What is the empirical formula of the compound? Nz O3 5. Mercury chlorine contains 73.9% mercury and 26.1% chlorine by mass. What's the empirical formula of mercury chlorine? How to determine a Molecular Formula? 6. Mesitylene, a hydrocarbon found in crude oil, has an empirical formula of C3H4 and an experimentally determined molecular weight of 121 amu. What is its molecular formula?

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How to Calculate an Empirical Formula from Percentage?
Given:
Find:
Assume
Mass %
Use
Grams of
each element
100-g
sample
Empirical
formula
Calculate
mole ratio
Moles of
each element
elements
molar
mass
3.
4. A molecule containing only nitrogen and oxygen contains (by mass) 36.8% N.
a) How many grams of N would be found in a 100 g sample of the compound?
100g x 36.8 = 36.89N
How many grams of O would be found in the same sample?
L03.290
100S-30.89 = lo3.2g0
b) How many moles of N would be found in a 100 g sample of the compound?
Imol NatoYS
36.89+DO l679
= Z,663 mol Natoms
14,00679 g N atoms
How many moles of O would be found in the same sample?
63.29) Imol D atoms
15.99949 O atoms
= 3.95 mor O atorrs
c) What is the ratio of the number of moles of O to the number of moles of N?
=1.5=12 =30
2 N
3.95 Datoms
%3D
11
2.663 N atoms
d) What is the empirical formula of the compound?
Nz O3
5. Mercury chlorine contains 73.9% mercury and 26.1% chlorine by mass. What's the
empirical formula of mercury chlorine?
How to determine a Molecular Formula?
6. Mesitylene, a hydrocarbon found in crude oil, has an empirical formula of C3H4 and an
experimentally determined molecular weight of 121 amu. What is its molecular formula?
Transcribed Image Text:How to Calculate an Empirical Formula from Percentage? Given: Find: Assume Mass % Use Grams of each element 100-g sample Empirical formula Calculate mole ratio Moles of each element elements molar mass 3. 4. A molecule containing only nitrogen and oxygen contains (by mass) 36.8% N. a) How many grams of N would be found in a 100 g sample of the compound? 100g x 36.8 = 36.89N How many grams of O would be found in the same sample? L03.290 100S-30.89 = lo3.2g0 b) How many moles of N would be found in a 100 g sample of the compound? Imol NatoYS 36.89+DO l679 = Z,663 mol Natoms 14,00679 g N atoms How many moles of O would be found in the same sample? 63.29) Imol D atoms 15.99949 O atoms = 3.95 mor O atorrs c) What is the ratio of the number of moles of O to the number of moles of N? =1.5=12 =30 2 N 3.95 Datoms %3D 11 2.663 N atoms d) What is the empirical formula of the compound? Nz O3 5. Mercury chlorine contains 73.9% mercury and 26.1% chlorine by mass. What's the empirical formula of mercury chlorine? How to determine a Molecular Formula? 6. Mesitylene, a hydrocarbon found in crude oil, has an empirical formula of C3H4 and an experimentally determined molecular weight of 121 amu. What is its molecular formula?
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