how this boolean expression works in what terms of the laws?: x'y'z' + x'y'z + x'yz + xy'z = x'y'(z+z') + z(x'y + xy') = x'y' + x'z + y'z   I understood z+z' becomes 1 by the the inverse law, but how z(x'y + xy') goes x'z + y'z?

Q: Simplify the following Boolean expression. F(x, y, z) = xy' + yz' +x'y'z'

A: Q1.  F= xy'+yz'+x'y'z' = xy'+z'(y+y'x')  = xy'+z'(y+x')  = xy' + yz' + x'z' = xy'+z' Option (b) is…

Q: For the function, F(x, y, z) = (x + z)' + (3/ z) + (xz)' , %3D simplify it using Boolean algebra…

A:

Q: Write a simplified expression for the Boolean function defined by the following Kmap. You need to…

A: Answer: We need to write the minimal expression for the sum of product and product of sum so we will…

Q: Write a simplified expression for the Boolean function defined by the following Kmap. You need to…

A: Answer: We need to write the minimal expression for the sum of product and product of sum so we will…

Q: What is the appropriate Boolean algebra property? DeMorgan Distributive  Null Involution  identity…

A: Given: DeMorgan Distributive  Null Involution  identity  Complement  Associative  Commutative…

Q: F(x, y, z) = xz + x'y' + y'z' F(x, y, z) = (x' + y + z')' + xy'z' + yz + xyz  F(x, y, z) = x'yz +…

A: boolean functions using Boolean algebra and its identities

Q: Simplify Boolean function using K map. Variables are marked in order of xyz

A: Here we can form group of 4 bits at once.