how that the given set V is closed under addition and multiplication by scalars and is therefore a subspace of R. is the set of all et a = X ххо X 0 y Z y and b = such that z = 0. u V 0 be two vectors in V. Find their sum a + b. x+u +b= y+v (Simplify your answer.) 0 ne vector sum a + b ddition. ype an integer or a fraction.) ▼an element of the set V because it its third component equal to Therefore, V is closed und
how that the given set V is closed under addition and multiplication by scalars and is therefore a subspace of R. is the set of all et a = X ххо X 0 y Z y and b = such that z = 0. u V 0 be two vectors in V. Find their sum a + b. x+u +b= y+v (Simplify your answer.) 0 ne vector sum a + b ddition. ype an integer or a fraction.) ▼an element of the set V because it its third component equal to Therefore, V is closed und
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.4: The Dot Product
Problem 46E
Related questions
Question
![Show that the given set V is closed under addition and multiplication by scalars and is therefore a subspace of R
of R³.
V is the set of all
Let a =
a+b=
X
X
+++
y
0
and b =
x+u
y+v
0
such that z=0.
u
0
be two vectors in V. Find their sum a + b.
(Simplify your answer.)
The vector sum a + b
addition.
(Type an integer or a fraction.)
an element of the set V because it
its third component equal to
Therefore, V is closed under](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F918808b3-3bab-4c24-a49a-fe439aaeecc0%2F247fb145-9c4c-493e-be4b-c23ec2d950c6%2F9hkqo14_processed.png&w=3840&q=75)
Transcribed Image Text:Show that the given set V is closed under addition and multiplication by scalars and is therefore a subspace of R
of R³.
V is the set of all
Let a =
a+b=
X
X
+++
y
0
and b =
x+u
y+v
0
such that z=0.
u
0
be two vectors in V. Find their sum a + b.
(Simplify your answer.)
The vector sum a + b
addition.
(Type an integer or a fraction.)
an element of the set V because it
its third component equal to
Therefore, V is closed under
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