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How strong is the data? Did it agree or disagree?

How strong is the data? Did it agree or disagree?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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How strong is the data? Did it agree or disagree?
6:39 Data Table 3.3. Varying the Centripetal Force ..... Time needed Time needed to Centripetal Force mg (in N) Trial with to make 1 make 10 (in 1/sec') Hanging mass, (kg) Revolution Revolutions - Period, T (in sec) (in sec) 0.030 kg 0.294 N 19.28s 1.928s 0.2690 0.040 kg 0.392 N 15.35s 1.535s 0.4244 0.050 kg 0.49 N 13.59s 1.359s 0.5414 ------ -. 0.060 kg 0.588 N 12.73s 1.273s 0.6171 .... 0.070 kg 0.686 N 11.69s 1.169s 0.7318
Transcribed Image Text:6:39 Data Table 3.3. Varying the Centripetal Force ..... Time needed Time needed to Centripetal Force mg (in N) Trial with to make 1 make 10 (in 1/sec') Hanging mass, (kg) Revolution Revolutions - Period, T (in sec) (in sec) 0.030 kg 0.294 N 19.28s 1.928s 0.2690 0.040 kg 0.392 N 15.35s 1.535s 0.4244 0.050 kg 0.49 N 13.59s 1.359s 0.5414 ------ -. 0.060 kg 0.588 N 12.73s 1.273s 0.6171 .... 0.070 kg 0.686 N 11.69s 1.169s 0.7318
6:39 Table 3.4. Results (Varying the Centripetal Force). Mass of the Brass Object. = 0. 208 kg m, - 208.19g g to kg: g/1000 : 208.19/ 1000 : 0.20819 kg 0.208 kg Slope of the trendline (from the graph Fe vs.1T) slope, m(F, T') = 0.882 N m. [computed using the slope,m (F.T)) m, = 0. 22 N slope,m (FCT³) = 0.882 radius, r= 0.994 = 0.882N 4п2 (0.994) m. = 0.022 N
Transcribed Image Text:6:39 Table 3.4. Results (Varying the Centripetal Force). Mass of the Brass Object. = 0. 208 kg m, - 208.19g g to kg: g/1000 : 208.19/ 1000 : 0.20819 kg 0.208 kg Slope of the trendline (from the graph Fe vs.1T) slope, m(F, T') = 0.882 N m. [computed using the slope,m (F.T)) m, = 0. 22 N slope,m (FCT³) = 0.882 radius, r= 0.994 = 0.882N 4п2 (0.994) m. = 0.022 N
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