How much pressure in Pascal does a diver feel 5.5 meters below sea water surface, that is the pressure above atmospheric pressure at that depth? Density of sea water is 1,120 kg/m^3. Gravity is 9.8 m/s^2

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**Question:**

How much pressure in Pascal does a diver feel 5.5 meters below sea water surface, that is the pressure above atmospheric pressure at that depth?

Density of sea water is 1,120 kg/m^3. Gravity is 9.8 m/s^2.

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In this scenario, we are asked to find the pressure exerted on a diver at a depth of 5.5 meters below the sea surface, ignoring atmospheric pressure. We can use the formula for hydrostatic pressure to find this value:

\[ P = \rho g h \]

where:
- \( P \) is the pressure difference in Pascals (Pa).
- \( \rho \) is the density of the fluid (sea water in this case), given as 1,120 kg/m\(^3\).
- \( g \) is the acceleration due to gravity, given as 9.8 m/s\(^2\).
- \( h \) is the depth below the surface, given as 5.5 meters.

Plugging in the given values:

\[ P = 1,120 \, \text{kg/m}^3 \times 9.8 \, \text{m/s}^2 \times 5.5 \, \text{m} \]

Calculating this:

\[ P = 1,120 \times 9.8 \times 5.5 \]
\[ P = 60,368 \, \text{Pa} \]

So, the pressure that a diver feels 5.5 meters below the sea water surface, above atmospheric pressure, is 60,368 Pascals (Pa).
Transcribed Image Text:**Question:** How much pressure in Pascal does a diver feel 5.5 meters below sea water surface, that is the pressure above atmospheric pressure at that depth? Density of sea water is 1,120 kg/m^3. Gravity is 9.8 m/s^2. --- In this scenario, we are asked to find the pressure exerted on a diver at a depth of 5.5 meters below the sea surface, ignoring atmospheric pressure. We can use the formula for hydrostatic pressure to find this value: \[ P = \rho g h \] where: - \( P \) is the pressure difference in Pascals (Pa). - \( \rho \) is the density of the fluid (sea water in this case), given as 1,120 kg/m\(^3\). - \( g \) is the acceleration due to gravity, given as 9.8 m/s\(^2\). - \( h \) is the depth below the surface, given as 5.5 meters. Plugging in the given values: \[ P = 1,120 \, \text{kg/m}^3 \times 9.8 \, \text{m/s}^2 \times 5.5 \, \text{m} \] Calculating this: \[ P = 1,120 \times 9.8 \times 5.5 \] \[ P = 60,368 \, \text{Pa} \] So, the pressure that a diver feels 5.5 meters below the sea water surface, above atmospheric pressure, is 60,368 Pascals (Pa).
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