Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Educational Content: Preparing a Potassium Hydroxide Solution**
**Question:**
How much potassium hydroxide is needed to make 1.00 L of a 2 molar solution of potassium hydroxide?
*In this handwritten note, a calculation question is posed. The user is asked to determine the amount of potassium hydroxide (KOH) required to prepare 1.00 liter of a 2 molar (2M) KOH solution.*
Overall, the transcription process, including the question and any accompanying diagrams, would comprise a step-by-step educational content that can be used for teaching purposes.
**Steps to Solve:**
1. **Definition of Molarity:**
Molarity (M) is defined as the number of moles of solute per liter of solution.
\[
M = \frac{\text{moles of solute}}{\text{liters of solution}}
\]
2. **Given Values:**
- Volume of solution (V) = 1.00 L
- Molarity of solution (M) = 2 M
3. **Formula to Find Moles of Solute:**
\[
\text{Moles of KOH} = M \times V
\]
Substituting the given values:
\[
\text{Moles of KOH} = 2 \, \text{M} \times 1.00 \, \text{L} = 2 \, \text{moles}
\]
4. **Calculate the Mass of Potassium Hydroxide (KOH):**
The molar mass of KOH (potassium hydroxide) needs to be known. The molar mass of KOH is:
- Potassium (K): 39.10 g/mol
- Oxygen (O): 16.00 g/mol
- Hydrogen (H): 1.01 g/mol
\[
\text{Molar Mass of KOH} = 39.10 + 16.00 + 1.01 = 56.11 \, \text{g/mol}
\]
5. **Mass of KOH Required:**
\[
\text{Mass of KOH} = \text{moles of KOH} \times \text{molar mass of KOH}
\]
Substit](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf4fd61a-46d9-45b2-8502-88fe4eac45cd%2F39befaa8-b5a2-4640-b3ad-778502b20959%2Foe4thy8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Educational Content: Preparing a Potassium Hydroxide Solution**
**Question:**
How much potassium hydroxide is needed to make 1.00 L of a 2 molar solution of potassium hydroxide?
*In this handwritten note, a calculation question is posed. The user is asked to determine the amount of potassium hydroxide (KOH) required to prepare 1.00 liter of a 2 molar (2M) KOH solution.*
Overall, the transcription process, including the question and any accompanying diagrams, would comprise a step-by-step educational content that can be used for teaching purposes.
**Steps to Solve:**
1. **Definition of Molarity:**
Molarity (M) is defined as the number of moles of solute per liter of solution.
\[
M = \frac{\text{moles of solute}}{\text{liters of solution}}
\]
2. **Given Values:**
- Volume of solution (V) = 1.00 L
- Molarity of solution (M) = 2 M
3. **Formula to Find Moles of Solute:**
\[
\text{Moles of KOH} = M \times V
\]
Substituting the given values:
\[
\text{Moles of KOH} = 2 \, \text{M} \times 1.00 \, \text{L} = 2 \, \text{moles}
\]
4. **Calculate the Mass of Potassium Hydroxide (KOH):**
The molar mass of KOH (potassium hydroxide) needs to be known. The molar mass of KOH is:
- Potassium (K): 39.10 g/mol
- Oxygen (O): 16.00 g/mol
- Hydrogen (H): 1.01 g/mol
\[
\text{Molar Mass of KOH} = 39.10 + 16.00 + 1.01 = 56.11 \, \text{g/mol}
\]
5. **Mass of KOH Required:**
\[
\text{Mass of KOH} = \text{moles of KOH} \times \text{molar mass of KOH}
\]
Substit
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