Living By Chemistry: First Edition Textbook
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ISBN:9781559539418
Author:Angelica Stacy
Publisher:Angelica Stacy
ChapterU5: Fire: Energy , Thermodynamics, And Oxidation-reduction
Section: Chapter Questions
Problem SI8RE
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![**Question:**
How much heat is required to raise the temperature of 25g of water from 25.0°C to 30.0°C? The specific heat of water is 4.184J/g°C.
**Explanation:**
To determine the amount of heat (Q) required to raise the temperature of a substance, you can use the specific heat formula:
\[ Q = mc\Delta T \]
Where:
- \( Q \) is the heat added (in Joules, J)
- \( m \) is the mass of the water (in grams, g)
- \( c \) is the specific heat capacity (in Joules per gram per degree Celsius, J/g°C)
- \( \Delta T \) is the change in temperature (in degrees Celsius, °C)
In this problem:
- The mass \( m \) is 25g
- The specific heat capacity \( c \) of water is 4.184J/g°C
- The change in temperature \( \Delta T \) is \( 30.0°C - 25.0°C = 5.0°C \)
By substituting these values into the formula, we get:
\[ Q = 25 \text{g} \times 4.184 \text{J/g°C} \times 5.0°C \]
\[ Q = 523 \text{J} \]
Therefore, the heat required to raise the temperature of 25g of water from 25.0°C to 30.0°C is 523 Joules.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F16ab444c-cc67-4b2e-a5c5-3a02b2df29f8%2Fad4ccddc-f892-418e-a04f-3c64a160c4e7%2F8gzilhv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
How much heat is required to raise the temperature of 25g of water from 25.0°C to 30.0°C? The specific heat of water is 4.184J/g°C.
**Explanation:**
To determine the amount of heat (Q) required to raise the temperature of a substance, you can use the specific heat formula:
\[ Q = mc\Delta T \]
Where:
- \( Q \) is the heat added (in Joules, J)
- \( m \) is the mass of the water (in grams, g)
- \( c \) is the specific heat capacity (in Joules per gram per degree Celsius, J/g°C)
- \( \Delta T \) is the change in temperature (in degrees Celsius, °C)
In this problem:
- The mass \( m \) is 25g
- The specific heat capacity \( c \) of water is 4.184J/g°C
- The change in temperature \( \Delta T \) is \( 30.0°C - 25.0°C = 5.0°C \)
By substituting these values into the formula, we get:
\[ Q = 25 \text{g} \times 4.184 \text{J/g°C} \times 5.0°C \]
\[ Q = 523 \text{J} \]
Therefore, the heat required to raise the temperature of 25g of water from 25.0°C to 30.0°C is 523 Joules.
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