How much heat (in kJ) is required to warm 16.0g of ice, initially at -14.0 degree Celsius, to steam at 115 degree Celsius? The heat capacity of ice is 2.09 J/ g*C and heat capacity of steam is 2.01J/g*C (answer in kJ and 3 sigfigs)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
icon
Concept explainers
Question
100%

How much heat (in kJ) is required to warm 16.0g of ice, initially at -14.0 degree Celsius, to steam at 115 degree Celsius? The heat capacity of ice is 2.09 J/ g*C and heat capacity of steam is 2.01J/g*C

(answer in kJ and 3 sigfigs)

My attempt equaled 7680.04 kJ but is incorrect, thank you for the help

F
3) how
16.0
g
how much heat (KJ) is required to warm
at 115 °C ?
of ice, initially at -14°C, to steam
the heat capacity of ice is
-1
and
2.095.g²¹.c
is 2.015.g¹.c ²
D
2
3
S
O
the that of steam
[KS to ssig figs]
8₁-
mc AT
(warm to melting point)
tq ₁ =
9₁ = (16.05) (2.095/9.c) (0.0°7--14°c)
468.16
16.08h00 x
= 0.8879
2
q₂ = AHFUS * mol
(6.023) (0.88791) = S. 345172031KS
imcl
18.028
93= MC AT
(warm to boiling point)
(16.05 )( 4.18 3/9-c) ( 100°C -0.0⁰)
83= 6682
8₁ = Autlvap xmol
9 ₁ = (40.715 /mol ) ( 0.8879)
(Phase change)
84 = 136 137 534 J
8 5 = MCAT
(16.09) (2.01 3/g.c) ( 115 - 100
qs =
482.4 к5
Total: 7680.042702 KS
(wam to gas)
Transcribed Image Text:F 3) how 16.0 g how much heat (KJ) is required to warm at 115 °C ? of ice, initially at -14°C, to steam the heat capacity of ice is -1 and 2.095.g²¹.c is 2.015.g¹.c ² D 2 3 S O the that of steam [KS to ssig figs] 8₁- mc AT (warm to melting point) tq ₁ = 9₁ = (16.05) (2.095/9.c) (0.0°7--14°c) 468.16 16.08h00 x = 0.8879 2 q₂ = AHFUS * mol (6.023) (0.88791) = S. 345172031KS imcl 18.028 93= MC AT (warm to boiling point) (16.05 )( 4.18 3/9-c) ( 100°C -0.0⁰) 83= 6682 8₁ = Autlvap xmol 9 ₁ = (40.715 /mol ) ( 0.8879) (Phase change) 84 = 136 137 534 J 8 5 = MCAT (16.09) (2.01 3/g.c) ( 115 - 100 qs = 482.4 к5 Total: 7680.042702 KS (wam to gas)
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

Blurred answer
Knowledge Booster
Thermochemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY