College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Question 4:**
How much force was required to bring granny’s 1200-kg car to rest from 90 mph (40 m/s) in 2 seconds?
**Explanation:**
This question asks you to calculate the force needed to bring a car weighing 1200 kg to a stop from a speed of 40 meters per second over a duration of 2 seconds. We utilize the formula derived from Newton's Second Law:
\[ \text{Force (F)} = \frac{\Delta v}{\Delta t} \times m \]
Where:
- \( \Delta v \) is the change in velocity.
- \( \Delta t \) is the change in time.
- \( m \) is the mass of the car.
The car's velocity changes from 40 m/s to 0 m/s, so \( \Delta v = 40 - 0 = 40 \) m/s. The given time \( \Delta t = 2 \) seconds, and the mass \( m = 1200 \) kg.
Plug these values into the formula:
\[ \text{Force (F)} = \frac{40 \, \text{m/s}}{2 \, \text{s}} \times 1200 \, \text{kg} \]
\[ \text{Force (F)} = 20 \, \text{m/s}^2 \times 1200 \, \text{kg} \]
\[ \text{Force (F)} = 24000 \, \text{N} \]
Thus, a force of 24,000 Newtons is needed.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4b08cbe3-b052-4a50-ae7b-da07c66e348c%2F12fec664-c002-4ef0-af37-8ffcded58af8%2Fmjhrmur_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 4:**
How much force was required to bring granny’s 1200-kg car to rest from 90 mph (40 m/s) in 2 seconds?
**Explanation:**
This question asks you to calculate the force needed to bring a car weighing 1200 kg to a stop from a speed of 40 meters per second over a duration of 2 seconds. We utilize the formula derived from Newton's Second Law:
\[ \text{Force (F)} = \frac{\Delta v}{\Delta t} \times m \]
Where:
- \( \Delta v \) is the change in velocity.
- \( \Delta t \) is the change in time.
- \( m \) is the mass of the car.
The car's velocity changes from 40 m/s to 0 m/s, so \( \Delta v = 40 - 0 = 40 \) m/s. The given time \( \Delta t = 2 \) seconds, and the mass \( m = 1200 \) kg.
Plug these values into the formula:
\[ \text{Force (F)} = \frac{40 \, \text{m/s}}{2 \, \text{s}} \times 1200 \, \text{kg} \]
\[ \text{Force (F)} = 20 \, \text{m/s}^2 \times 1200 \, \text{kg} \]
\[ \text{Force (F)} = 24000 \, \text{N} \]
Thus, a force of 24,000 Newtons is needed.
Expert Solution

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Given Data:
Mass of car
Velocity of car
Time
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