How much force was required to bring granny's 1200-kg car to rest from 90 mph (40 m/s) in 2 seconds?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Topic Video
Question
**Question 4:**

How much force was required to bring granny’s 1200-kg car to rest from 90 mph (40 m/s) in 2 seconds?

**Explanation:**

This question asks you to calculate the force needed to bring a car weighing 1200 kg to a stop from a speed of 40 meters per second over a duration of 2 seconds. We utilize the formula derived from Newton's Second Law:

\[ \text{Force (F)} = \frac{\Delta v}{\Delta t} \times m \]

Where:
- \( \Delta v \) is the change in velocity. 
- \( \Delta t \) is the change in time.
- \( m \) is the mass of the car.

The car's velocity changes from 40 m/s to 0 m/s, so \( \Delta v = 40 - 0 = 40 \) m/s. The given time \( \Delta t = 2 \) seconds, and the mass \( m = 1200 \) kg.

Plug these values into the formula:

\[ \text{Force (F)} = \frac{40 \, \text{m/s}}{2 \, \text{s}} \times 1200 \, \text{kg} \]

\[ \text{Force (F)} = 20 \, \text{m/s}^2 \times 1200 \, \text{kg} \]

\[ \text{Force (F)} = 24000 \, \text{N} \]

Thus, a force of 24,000 Newtons is needed.
Transcribed Image Text:**Question 4:** How much force was required to bring granny’s 1200-kg car to rest from 90 mph (40 m/s) in 2 seconds? **Explanation:** This question asks you to calculate the force needed to bring a car weighing 1200 kg to a stop from a speed of 40 meters per second over a duration of 2 seconds. We utilize the formula derived from Newton's Second Law: \[ \text{Force (F)} = \frac{\Delta v}{\Delta t} \times m \] Where: - \( \Delta v \) is the change in velocity. - \( \Delta t \) is the change in time. - \( m \) is the mass of the car. The car's velocity changes from 40 m/s to 0 m/s, so \( \Delta v = 40 - 0 = 40 \) m/s. The given time \( \Delta t = 2 \) seconds, and the mass \( m = 1200 \) kg. Plug these values into the formula: \[ \text{Force (F)} = \frac{40 \, \text{m/s}}{2 \, \text{s}} \times 1200 \, \text{kg} \] \[ \text{Force (F)} = 20 \, \text{m/s}^2 \times 1200 \, \text{kg} \] \[ \text{Force (F)} = 24000 \, \text{N} \] Thus, a force of 24,000 Newtons is needed.
Expert Solution
Step 1

Given Data:

Mass of car m=1200 kg

Velocity of car v=90 mph=40 ms

Time t=2 sec

steps

Step by step

Solved in 3 steps

Blurred answer
Knowledge Booster
First law of motion
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON