How much energy is needed to convert 52.3 grams of ice at 0.00°C to water at 61.2°C? specific heat (ice) = 2.10 J/g°C specific heat (water) = 4.18 J/g °C heat of fusion = 333 J/g heat of vaporization = 2258 J/g NOTE: Answer must be in 3 significant figures and scientific notation. Units required. J Tip: you can use scientific/exponential notation to represent numeric values. Eg., -0.0001 can be written as 1.0e-4 or as 1.0E-4. Spaces are not allowed.
How much energy is needed to convert 52.3 grams of ice at 0.00°C to water at 61.2°C? specific heat (ice) = 2.10 J/g°C specific heat (water) = 4.18 J/g °C heat of fusion = 333 J/g heat of vaporization = 2258 J/g NOTE: Answer must be in 3 significant figures and scientific notation. Units required. J Tip: you can use scientific/exponential notation to represent numeric values. Eg., -0.0001 can be written as 1.0e-4 or as 1.0E-4. Spaces are not allowed.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:How much energy is needed to convert 52.3 grams of ice at 0.00°C to water at 61.2°C?
specific heat (ice) = 2.10 J/g °C
specific heat (water) = 4.18 J/g °C
heat of fusion = 333 J/g
heat of vaporization = 2258 J/g
NOTE: Answer must be in 3 significant figures and scientific notation. Units required.
Tip: you can use scientific/exponential notation to represent numeric values. Eg., -0.0001 can be written as 1.0e-4 or as 1.0E-4.
Spaces are not allowed.
Expert Solution
Step 1: Introduce
Temperature of ice = 0.00 0C =Ti
Final temperature = 61.2 0C
Mass of ice = 52.3 g
Specific heat of ice = 2.10 J/g. 0C
Specific heat of water = 4.18 J/g. 0C
heat of fusion = 333 J/g
Heat of vaporization = 2258 J/g
Latent heat is defined as the heat required to change the physical state of the substance and not the temperature.
Specific heat is required to change the temperature of a substance.
Here we have to calculate the amount of ice that would melt during the course of reaction.
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