How much energy is needed (in Joules) to convert 9.6 kg of ice at -31° C to water at 84°C? Specific heat of water, cwater = 4186 J/kg-C°,

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**Title: Calculating Energy Required for Phase Changes and Temperature Increases**

**Introduction:**

To understand how much energy is needed to convert ice to water and increase its temperature, let's explore the calculation involved in this transformation.

**Problem Statement:**

Calculate the energy required (in Joules) to convert 9.6 kg of ice at -31°C to water at 84°C.

**Given Values:**

- **Specific heat of water, \( c_{\text{water}} = 4186 \, \text{J/kg°C} \)**
- **Latent heat of fusion of ice, \( L_F = 3.33 \times 10^5 \, \text{J/kg} \)**
- **Specific heat of ice, \( c_{\text{ice}} = 2090 \, \text{J/kg°C} \)**

**Discussion:**

When converting ice at a sub-zero temperature to water above room temperature, the process involves several stages:

1. **Heating the ice from -31°C to 0°C.**
2. **Melting the ice at 0°C to form water.**
3. **Heating the resultant water from 0°C to 84°C.**

By calculating the energy for each stage and summing them up, we determine the total energy required. Each stage utilizes specific heat capacities and latent heat properties to facilitate these transformations.
Transcribed Image Text:**Title: Calculating Energy Required for Phase Changes and Temperature Increases** **Introduction:** To understand how much energy is needed to convert ice to water and increase its temperature, let's explore the calculation involved in this transformation. **Problem Statement:** Calculate the energy required (in Joules) to convert 9.6 kg of ice at -31°C to water at 84°C. **Given Values:** - **Specific heat of water, \( c_{\text{water}} = 4186 \, \text{J/kg°C} \)** - **Latent heat of fusion of ice, \( L_F = 3.33 \times 10^5 \, \text{J/kg} \)** - **Specific heat of ice, \( c_{\text{ice}} = 2090 \, \text{J/kg°C} \)** **Discussion:** When converting ice at a sub-zero temperature to water above room temperature, the process involves several stages: 1. **Heating the ice from -31°C to 0°C.** 2. **Melting the ice at 0°C to form water.** 3. **Heating the resultant water from 0°C to 84°C.** By calculating the energy for each stage and summing them up, we determine the total energy required. Each stage utilizes specific heat capacities and latent heat properties to facilitate these transformations.
**Formulas:**

**Specific Heat:**
- \( c \equiv \frac{Q}{m \Delta T} \)  (J/kg · °C)
- \( Q = mc(T_f - T_i) \)

**Mixtures:**
- \( Q_{\text{cold}} = -Q_{\text{hot}} \)

**Latent Heat:**
- Phase change: \( Q = \pm mL \)

**Thermal Conductivity:**
- \( Q/t = \text{Power} = P = kA \frac{(T_h - T_c)}{L} \)

**Stefan’s Law of Radiation:**
- \( P = \sigma A e T^4 \)

---

**Explanation:**

- **Specific Heat:** This set of equations is used to calculate the amount of heat (\(Q\)) required to change the temperature of a mass (\(m\)) by a certain temperature difference (\(\Delta T\)). The specific heat (\(c\)) is expressed in joules per kilogram per degree Celsius.
  
- **Mixtures:** This equation indicates that in a thermal mixture, the heat lost by the hot substance (\(Q_{\text{hot}}\)) equals the heat gained by the cold substance (\(Q_{\text{cold}}\)).

- **Latent Heat:** This formula is for phase changes, where \(L\) is the latent heat. The heat transferred (\(Q\)) during a phase change depends on the mass (\(m\)) and the latent heat of the substance.

- **Thermal Conductivity:** This equation calculates the power (\(P\)) or heat transfer rate, taking into account the conductivity (\(k\)), the area (\(A\)), and the temperature difference between the hot (\(T_h\)) and cold sides (\(T_c\)) over a distance (\(L\)).

- **Stefan’s Law of Radiation:** This formula describes the power (\(P\)) radiated by a body with area (\(A\)), emissivity (\(e\)), and temperature (\(T\)), using the Stefan-Boltzmann constant (\(\sigma\)).
Transcribed Image Text:**Formulas:** **Specific Heat:** - \( c \equiv \frac{Q}{m \Delta T} \) (J/kg · °C) - \( Q = mc(T_f - T_i) \) **Mixtures:** - \( Q_{\text{cold}} = -Q_{\text{hot}} \) **Latent Heat:** - Phase change: \( Q = \pm mL \) **Thermal Conductivity:** - \( Q/t = \text{Power} = P = kA \frac{(T_h - T_c)}{L} \) **Stefan’s Law of Radiation:** - \( P = \sigma A e T^4 \) --- **Explanation:** - **Specific Heat:** This set of equations is used to calculate the amount of heat (\(Q\)) required to change the temperature of a mass (\(m\)) by a certain temperature difference (\(\Delta T\)). The specific heat (\(c\)) is expressed in joules per kilogram per degree Celsius. - **Mixtures:** This equation indicates that in a thermal mixture, the heat lost by the hot substance (\(Q_{\text{hot}}\)) equals the heat gained by the cold substance (\(Q_{\text{cold}}\)). - **Latent Heat:** This formula is for phase changes, where \(L\) is the latent heat. The heat transferred (\(Q\)) during a phase change depends on the mass (\(m\)) and the latent heat of the substance. - **Thermal Conductivity:** This equation calculates the power (\(P\)) or heat transfer rate, taking into account the conductivity (\(k\)), the area (\(A\)), and the temperature difference between the hot (\(T_h\)) and cold sides (\(T_c\)) over a distance (\(L\)). - **Stefan’s Law of Radiation:** This formula describes the power (\(P\)) radiated by a body with area (\(A\)), emissivity (\(e\)), and temperature (\(T\)), using the Stefan-Boltzmann constant (\(\sigma\)).
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