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how me the steps of determine yellow and all information is her

how me the steps of determine yellow and all information is her

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Show me the steps of determine yellow and all information is here

 
e2n cn U8n-5 = an-1(c – e)"(a – c)n' f2n dn b2-1(d – f)"(b – d)n' U8n-4 = cn+1e2n U8n-3 = a"(a – c)"(c – e)n' dn+1 f2n b* (b – d)"(d – f)r e2n+1cn U8n-2 = U8n-1 = a" (a – c)"(c – e)n' f2n+1 dr b* (b – d)"(d – f)n' cn+1e2n+1 U8n U8n+1 а" (с— е)" (а — с)т+1" dn+1 f2n+1 b* (d – f)"(b – d)n+1* U8n+2 = This work aims to investigate the equilibria, local stability, global attractivity and the exact solutions of the following difference equations Bun-1un-5 Yun-3 - bun-5 Un+1 = QUn-1+ n = 0,1, ..., (1) Bun-1un-5 Un+1 = aun-1 n = 0,1, ..., (2) Yun-3 + ôun-5 where the coefficients a, B, y, and & are positive real numbers and the initial con- ditions u; for all i = -5, -4, .., 0, are arbitrary non-zero real numbers. We also present the numerical solutions via some 2D graphs. 2. ON THE EQUATION Un+1 = QUn-1 + Bun-1ün-5 Yun-3-bun-5 This section is devoted to study the qualitative behaviors of Eq. (1). The equilibrium point of Eq. (1) is given by Un-1un-5 Un+1 = Un-1+ n = 0, 1,..., (10) Un-3 - Un-5 d" f2n-2 -1(b – d)n-1(d – f)n-1’ e2n-1cn-1 U8n-10 = bn-1 U8n-9 = an-1(a – c)n-1(c – e)n-1' f2n-1an-1 -'(b – d)n-1(d – f)*-1’ c"e2n-1 U8n-8 = bn-1 U8n-7 = n-'(c – e)n-1(a – c)n' d" f2n-1 b2-1 (d – f)n-1(b- d)n' an- U8n-6 =
Transcribed Image Text:e2n cn U8n-5 = an-1(c – e)"(a – c)n' f2n dn b2-1(d – f)"(b – d)n' U8n-4 = cn+1e2n U8n-3 = a"(a – c)"(c – e)n' dn+1 f2n b* (b – d)"(d – f)r e2n+1cn U8n-2 = U8n-1 = a" (a – c)"(c – e)n' f2n+1 dr b* (b – d)"(d – f)n' cn+1e2n+1 U8n U8n+1 а" (с— е)" (а — с)т+1" dn+1 f2n+1 b* (d – f)"(b – d)n+1* U8n+2 = This work aims to investigate the equilibria, local stability, global attractivity and the exact solutions of the following difference equations Bun-1un-5 Yun-3 - bun-5 Un+1 = QUn-1+ n = 0,1, ..., (1) Bun-1un-5 Un+1 = aun-1 n = 0,1, ..., (2) Yun-3 + ôun-5 where the coefficients a, B, y, and & are positive real numbers and the initial con- ditions u; for all i = -5, -4, .., 0, are arbitrary non-zero real numbers. We also present the numerical solutions via some 2D graphs. 2. ON THE EQUATION Un+1 = QUn-1 + Bun-1ün-5 Yun-3-bun-5 This section is devoted to study the qualitative behaviors of Eq. (1). The equilibrium point of Eq. (1) is given by Un-1un-5 Un+1 = Un-1+ n = 0, 1,..., (10) Un-3 - Un-5 d" f2n-2 -1(b – d)n-1(d – f)n-1’ e2n-1cn-1 U8n-10 = bn-1 U8n-9 = an-1(a – c)n-1(c – e)n-1' f2n-1an-1 -'(b – d)n-1(d – f)*-1’ c"e2n-1 U8n-8 = bn-1 U8n-7 = n-'(c – e)n-1(a – c)n' d" f2n-1 b2-1 (d – f)n-1(b- d)n' an- U8n-6 =
Furthermore, Eq. (10) gives us U8n-5U8n-9 U8n-3 = U8n-5 + U8n-7 - U8n-9 2n „n e2n-1n-1 e2n cn an-1(c-e)"(a-c)" an-1(a-c)n–1(c-e)n-I cne2n-1 aп-1(с — е)т (а — с)" e2n–1 cn-1 an-1(a-c)n-1 (c-e)n-I an-1(c-e)n-1(a-c)" e2n cn e2n cn ат-1(с — е)" (а — с)п e2n cn a" (с — е)"(а — с)"-1 a а — с (с — е)"(а — с)" e2n cn+1 а" (с — е)"(а — с)п an an %3D Also, Eq. (10) leads to U8n-4u8n-8 U8n-2 = Ug8n-4 + U8n-6 - U8n-8 f2n dn bn-1(d – f)"(b – d)n f2n-1 an-1 bn-1 (d-f)" (b-d)n bn-1(b-d)n–1(d-f)n-I f2n-1 dn-1 bn-1 (b-d)n-1(d-f)n-I dn f2n-1 bn–1 (d-f)n-1(b-d)n f2m dn bn-1(d – f)"(b – d)" f2n dn b" (d – f)"(b – d)" f2n dn br (d – f)"(b – d)n-1 1 (b – d)-1 f2n ɑn+1 b" (d – f)" (b – d)" Moreover, Eq. (10) gives U8n-3u8n-7 U8n-1 = U8n-3 + U8n-5 - U8n-7 cn+1,2n a" (a-c)"(c-e)" c"2n-1 an-1(c-e)n-1(a-c)" cn+1_2n а" (а — с)"(с — е)т c"e2n-1 an-1(c-e)n-(a-c)n e2n cn an-1(c-e)" (a-c)" cn+1e2n c"e2n а" (а — с)" (с — е)т a"(с — е)п-1(а — с)" (1 + е) cn+1e2n c"e2n а" (а — с)"(с — е)" а"(с — е)"-1(а — с)" c"e2n+1 а" (а — с)"(с — е)"" Finally, Eq. (10) gives
Transcribed Image Text:Furthermore, Eq. (10) gives us U8n-5U8n-9 U8n-3 = U8n-5 + U8n-7 - U8n-9 2n „n e2n-1n-1 e2n cn an-1(c-e)"(a-c)" an-1(a-c)n–1(c-e)n-I cne2n-1 aп-1(с — е)т (а — с)" e2n–1 cn-1 an-1(a-c)n-1 (c-e)n-I an-1(c-e)n-1(a-c)" e2n cn e2n cn ат-1(с — е)" (а — с)п e2n cn a" (с — е)"(а — с)"-1 a а — с (с — е)"(а — с)" e2n cn+1 а" (с — е)"(а — с)п an an %3D Also, Eq. (10) leads to U8n-4u8n-8 U8n-2 = Ug8n-4 + U8n-6 - U8n-8 f2n dn bn-1(d – f)"(b – d)n f2n-1 an-1 bn-1 (d-f)" (b-d)n bn-1(b-d)n–1(d-f)n-I f2n-1 dn-1 bn-1 (b-d)n-1(d-f)n-I dn f2n-1 bn–1 (d-f)n-1(b-d)n f2m dn bn-1(d – f)"(b – d)" f2n dn b" (d – f)"(b – d)" f2n dn br (d – f)"(b – d)n-1 1 (b – d)-1 f2n ɑn+1 b" (d – f)" (b – d)" Moreover, Eq. (10) gives U8n-3u8n-7 U8n-1 = U8n-3 + U8n-5 - U8n-7 cn+1,2n a" (a-c)"(c-e)" c"2n-1 an-1(c-e)n-1(a-c)" cn+1_2n а" (а — с)"(с — е)т c"e2n-1 an-1(c-e)n-(a-c)n e2n cn an-1(c-e)" (a-c)" cn+1e2n c"e2n а" (а — с)" (с — е)т a"(с — е)п-1(а — с)" (1 + е) cn+1e2n c"e2n а" (а — с)"(с — е)" а"(с — е)"-1(а — с)" c"e2n+1 а" (а — с)"(с — е)"" Finally, Eq. (10) gives
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