How many years will it take for an initial investment of $20,000 to grow to $50,000? Assume a rate of interest of 11% compounded continuously. It will take about years for the investment to grow to $50,000. (Round to two decimal places as needed.)
Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 miles away.
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experiments to set up the devices.
![### Compound Interest Growth Calculation
**Problem Statement:**
How many years will it take for an initial investment of $20,000 to grow to $50,000? Assume a rate of interest of 11% compounded continuously.
**Solution:**
The formula for continuous compounding is given by:
\[ A = P e^{rt} \]
where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money, which is $20,000).
- \( r \) is the annual interest rate (decimal), which in this case is 11%, or 0.11.
- \( t \) is the time the money is invested for in years.
- \( e \) is the base of the natural logarithm, approximately equal to 2.71828.
We need to solve for \( t \) when \( A \) (the final amount) is $50,000.
So,
\[ 50,000 = 20,000 \times e^{0.11 t} \]
Divide both sides by 20,000:
\[ \frac{50,000}{20,000} = e^{0.11 t} \]
Simplify:
\[ 2.5 = e^{0.11 t} \]
Taking the natural logarithm on both sides:
\[ \ln(2.5) = \ln(e^{0.11 t}) \]
By the properties of logarithms:
\[ \ln(2.5) = 0.11 t \]
Therefore,
\[ t = \frac{\ln(2.5)}{0.11} \]
Calculate the value (using a calculator):
\[ t \approx \frac{0.916}{0.11} \]
\[ t \approx 8.33 \]
So, it will take about 8.33 years for the investment to grow to $50,000.
**Final Answer:**
It will take about \(\boxed{8.33}\) years for the investment to grow to $50,000.
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