Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
Question
![### Simplifying Algebraic Expressions
**Problem Statement:**
How many twenty-dollar bills would have a value of \$(60x - 40)? (Simplify your answer completely.)
**Explanation:**
To solve this problem, you need to determine the total value expressed by the algebraic expression \(60x - 40\) dollars and then find how many twenty-dollar bills are equivalent to this amount. Here are the steps you can follow:
1. **Simplify the Expression**:
- Combine like terms in the expression \(60x - 40\).
2. **Value in Terms of Twenty-Dollar Bills**:
- Divide the simplified expression by 20 (since each twenty-dollar bill is worth $20).
- This division will give you the number of twenty-dollar bills that make up the given amount.
**Solution**:
1. Given expression: \(60x - 40\) dollars
2. To find how many twenty-dollar bills make up this value, divide this by 20:
\[
\frac{60x - 40}{20}
\]
3. Simplify the fraction:
\[
\frac{60x}{20} - \frac{40}{20}
\]
4. Perform the division:
\[
3x - 2
\]
So, \(3x - 2\) twenty-dollar bills are equivalent to the given expression \((60x - 40)\) dollars.
**Conclusion**:
The number of twenty-dollar bills that would have the value of \((60x - 40)\) dollars is \((3x - 2)\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcfa510ce-a779-4198-b3d3-c9e941c192c9%2Fe62f88cf-001c-4382-bd51-be4ac09fa020%2Ft06mur_processed.png&w=3840&q=75)
Transcribed Image Text:### Simplifying Algebraic Expressions
**Problem Statement:**
How many twenty-dollar bills would have a value of \$(60x - 40)? (Simplify your answer completely.)
**Explanation:**
To solve this problem, you need to determine the total value expressed by the algebraic expression \(60x - 40\) dollars and then find how many twenty-dollar bills are equivalent to this amount. Here are the steps you can follow:
1. **Simplify the Expression**:
- Combine like terms in the expression \(60x - 40\).
2. **Value in Terms of Twenty-Dollar Bills**:
- Divide the simplified expression by 20 (since each twenty-dollar bill is worth $20).
- This division will give you the number of twenty-dollar bills that make up the given amount.
**Solution**:
1. Given expression: \(60x - 40\) dollars
2. To find how many twenty-dollar bills make up this value, divide this by 20:
\[
\frac{60x - 40}{20}
\]
3. Simplify the fraction:
\[
\frac{60x}{20} - \frac{40}{20}
\]
4. Perform the division:
\[
3x - 2
\]
So, \(3x - 2\) twenty-dollar bills are equivalent to the given expression \((60x - 40)\) dollars.
**Conclusion**:
The number of twenty-dollar bills that would have the value of \((60x - 40)\) dollars is \((3x - 2)\).
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