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How many moles of NO, would be produced from 4.5 mol of O2 in the reaction below assuming the reaction has a 57.0% yield? 2 NO (g) + O2 (g) → 2 NO2 (g)

How many moles of NO, would be produced from 4.5 mol of O2 in the reaction below assuming the reaction has a 57.0% yield? 2 NO (g) + O2 (g) → 2 NO2 (g)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question 14 of 20** **How many moles of NO₂ would be produced from 4.5 mol of O₂ in the reaction below assuming the reaction has a 57.0% yield?** Reaction: \[ 2 \, \text{NO (g)} + \text{O}_2 \, \text{(g)} \rightarrow 2 \, \text{NO}_2 \, \text{(g)} \] **Answer:** 3.9 mol --- **Details:** This problem involves stoichiometry and yield calculation in a balanced chemical reaction: 1. **Balanced Equation:** - 2 moles of NO react with 1 mole of O₂ to produce 2 moles of NO₂. 2. **Stoichiometric Calculation:** - According to the reaction, 1 mole of O₂ yields 2 moles of NO₂. - Therefore, 4.5 moles of O₂ would ideally produce \(4.5 \times 2 = 9\) moles of NO₂. 3. **Yield Calculation:** - With a 57.0% reaction yield: - \(9 \times 0.57 = 5.13\) moles of NO₂. 4. **Entered Answer:** - The entered answer here is 3.9 mol, which appears to account for additional details not specified, such as significant figures or other rounding considerations.
Transcribed Image Text:**Question 14 of 20** **How many moles of NO₂ would be produced from 4.5 mol of O₂ in the reaction below assuming the reaction has a 57.0% yield?** Reaction: \[ 2 \, \text{NO (g)} + \text{O}_2 \, \text{(g)} \rightarrow 2 \, \text{NO}_2 \, \text{(g)} \] **Answer:** 3.9 mol --- **Details:** This problem involves stoichiometry and yield calculation in a balanced chemical reaction: 1. **Balanced Equation:** - 2 moles of NO react with 1 mole of O₂ to produce 2 moles of NO₂. 2. **Stoichiometric Calculation:** - According to the reaction, 1 mole of O₂ yields 2 moles of NO₂. - Therefore, 4.5 moles of O₂ would ideally produce \(4.5 \times 2 = 9\) moles of NO₂. 3. **Yield Calculation:** - With a 57.0% reaction yield: - \(9 \times 0.57 = 5.13\) moles of NO₂. 4. **Entered Answer:** - The entered answer here is 3.9 mol, which appears to account for additional details not specified, such as significant figures or other rounding considerations.
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