How many moles of H+ ions are present in 456 mL of 0.943 M nitric acid solution? mol H+

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Problem:**  
How many moles of H⁺ ions are present in 456 mL of 0.943 M nitric acid solution?

**Solution Box:**  
\[ \text{______ mol H⁺} \]

**Explanation:**  
To determine the number of moles of H⁺ ions, use the formula:

\[
\text{Moles of H⁺} = \text{Volume (L)} \times \text{Concentration (M)}
\]

Convert the volume from milliliters to liters:

\[
456 \, \text{mL} = 0.456 \, \text{L}
\]

Multiply the volume by the concentration:

\[
0.456 \, \text{L} \times 0.943 \, \text{M} = 0.430488 \, \text{mol}
\]

Therefore, there are approximately 0.430 moles of H⁺ ions in the solution.
Transcribed Image Text:**Problem:** How many moles of H⁺ ions are present in 456 mL of 0.943 M nitric acid solution? **Solution Box:** \[ \text{______ mol H⁺} \] **Explanation:** To determine the number of moles of H⁺ ions, use the formula: \[ \text{Moles of H⁺} = \text{Volume (L)} \times \text{Concentration (M)} \] Convert the volume from milliliters to liters: \[ 456 \, \text{mL} = 0.456 \, \text{L} \] Multiply the volume by the concentration: \[ 0.456 \, \text{L} \times 0.943 \, \text{M} = 0.430488 \, \text{mol} \] Therefore, there are approximately 0.430 moles of H⁺ ions in the solution.
Expert Solution
Step 1

Given data : 

Concentration of HNO= 0.943 M 

Volume of HNO3 = 456 mL = 0.456 L 

1mL = 10-3

1 M = mol L-1

 

 

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