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How many moles of compound are in 23.3 g of Na2B407 10H2O? mol The number of significant digits is set to 3; the tolerance is +/-2%

How many moles of compound are in 23.3 g of Na2B407 10H2O? mol The number of significant digits is set to 3; the tolerance is +/-2%

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How many moles of compound are in 23.3 g of Na2B4O7·10H2O?

### Educational Content: Determining Moles of a Compound **Question:** How many moles of compound are in 23.3 g of \( \text{Na}_2\text{B}_4\text{O}_7 \cdot 10\text{H}_2\text{O} \)? **Response Field:** - Input: [______] mol **Details:** - The number of significant digits is set to 3. - The tolerance is set at +/- 2%. ### Explanation: To find the number of moles of the compound, calculate the molar mass of \( \text{Na}_2\text{B}_4\text{O}_7 \cdot 10\text{H}_2\text{O} \) and use the formula: \[ \text{Moles} = \frac{\text{Mass (g)}}{\text{Molar Mass (g/mol)}} \] Ensure your answer accounts for significant digits and falls within the specified tolerance.
Transcribed Image Text:### Educational Content: Determining Moles of a Compound **Question:** How many moles of compound are in 23.3 g of \( \text{Na}_2\text{B}_4\text{O}_7 \cdot 10\text{H}_2\text{O} \)? **Response Field:** - Input: [______] mol **Details:** - The number of significant digits is set to 3. - The tolerance is set at +/- 2%. ### Explanation: To find the number of moles of the compound, calculate the molar mass of \( \text{Na}_2\text{B}_4\text{O}_7 \cdot 10\text{H}_2\text{O} \) and use the formula: \[ \text{Moles} = \frac{\text{Mass (g)}}{\text{Molar Mass (g/mol)}} \] Ensure your answer accounts for significant digits and falls within the specified tolerance.
Expert Solution
Step 1

Mass of Na2B4O7·10H2O= 23.3 g

Element  Atomic mass
Na 22.989770
B 10.811
O 15.9994
H 1.00794

 

The molar mass of Na2B4O7·10H2O=22.98977 x 2 + 10.811 x 4 + 15.9994 x 7 + 10 x (1.00794 x 2 + 1 x 15.9994)

The molar mass of Na2B4O7·10H2O=381.3721 g/mol

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