How many moles of aluminum are required to completely react with 107 mL of 6.00 M H2SO, according to the balanced chemical reaction: 2 Al(s) + 3 H,SO (aq) Al2(SO4)3(aq) + 3 H2(9)

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Answered: Write the balan X
Answered: Write the balan X
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Question 11 of 25
How many moles of aluminum are required to completely react with 107
mL of
6.00 M H2SO4 according to the balanced chemical reaction:
2
Al(s) +
H2SO4(aq) → Al2(SO4)3(aq) + 3
H2(g)
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
%3D
98.08
1000
6.022 x 1023
6.00
0.963
1
428
107
0.001
0.428
0.0374
3
L H2SO4
M H2SO4
g Al2(SO4)3
mol H2
mL H2SO4
mol H2SO4
mol Al2(SO4)3
mol Al
g Al
g H2
g H2SO4
W
A Aa
PAGES
APR
1
275
11
Transcribed Image Text:Chrome Arquivo Editar Visualizar Histórico Favoritos Pessoas Guia Janela 101 Chem101 Ajuda Email – Camila Alexandre Answered: Write the balan X Answered: Write the balan X A app.101edu.co Write the balanced COMP X C Nitrate | NO3- Apps M Gmail YouTube Maps Traduzir GE Notícias Question 11 of 25 How many moles of aluminum are required to completely react with 107 mL of 6.00 M H2SO4 according to the balanced chemical reaction: 2 Al(s) + H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) %3D 98.08 1000 6.022 x 1023 6.00 0.963 1 428 107 0.001 0.428 0.0374 3 L H2SO4 M H2SO4 g Al2(SO4)3 mol H2 mL H2SO4 mol H2SO4 mol Al2(SO4)3 mol Al g Al g H2 g H2SO4 W A Aa PAGES APR 1 275 11
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