How many moles and numbers of ions of each type are present in the following aqueous solution? 51.7 mL of 1.35 M magnesium chloride: x 10 mol of magnesium x 10 magnesium ions x 10 mol of chloride x 10 chloride ions
How many moles and numbers of ions of each type are present in the following aqueous solution? 51.7 mL of 1.35 M magnesium chloride: x 10 mol of magnesium x 10 magnesium ions x 10 mol of chloride x 10 chloride ions
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How many moles and numbers of ions of each type are present in the following aqueous solution? 51.7 mL of 1.35 M magnesium chloride:
mol of magnesium
magnesium ions
mol of chloride
chloride ions
![**Educational Content: Calculating Moles and Ion Numbers in a Magnesium Chloride Solution**
---
**Problem Statement:**
How many moles and numbers of ions of each type are present in the following aqueous solution?
51.7 mL of 1.35 M magnesium chloride:
1. \(\_\_\_\_\_\) × 10\(^x\) mol of magnesium
2. \(\_\_\_\_\_\) × 10\(^x\) magnesium ions
3. \(\_\_\_\_\_\) × 10\(^x\) mol of chloride
4. \(\_\_\_\_\_\) × 10\(^x\) chloride ions
---
**Explanation:**
This exercise involves the calculation of the amount of substance in terms of moles and the corresponding number of ions in a given volume of magnesium chloride solution.
- **Magnesium Chloride (MgCl\(_2\))** dissociates completely in solution to produce one magnesium ion (Mg\(^{2+}\)) and two chloride ions (Cl\(^-\)) for each formula unit dissolved.
- The provided molarity (1.35 M) represents the concentration in moles per liter. To calculate the moles present in 51.7 mL, convert the volume to liters and use the formula:
\[
\text{Moles} = \text{Molarity} \times \text{Volume in liters}
\]
- Calculate the number of ions by considering Avogadro's number (6.022 × 10\(^{23}\) ions/mole) for each type of ion produced from the dissociation of magnesium chloride.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab95b8cd-e92c-4a9e-9ebe-46ce73f4a65e%2Fbab5554d-6e98-41f6-8352-3a7ec68b88b0%2Fem13dm4_processed.png&w=3840&q=75)
Transcribed Image Text:**Educational Content: Calculating Moles and Ion Numbers in a Magnesium Chloride Solution**
---
**Problem Statement:**
How many moles and numbers of ions of each type are present in the following aqueous solution?
51.7 mL of 1.35 M magnesium chloride:
1. \(\_\_\_\_\_\) × 10\(^x\) mol of magnesium
2. \(\_\_\_\_\_\) × 10\(^x\) magnesium ions
3. \(\_\_\_\_\_\) × 10\(^x\) mol of chloride
4. \(\_\_\_\_\_\) × 10\(^x\) chloride ions
---
**Explanation:**
This exercise involves the calculation of the amount of substance in terms of moles and the corresponding number of ions in a given volume of magnesium chloride solution.
- **Magnesium Chloride (MgCl\(_2\))** dissociates completely in solution to produce one magnesium ion (Mg\(^{2+}\)) and two chloride ions (Cl\(^-\)) for each formula unit dissolved.
- The provided molarity (1.35 M) represents the concentration in moles per liter. To calculate the moles present in 51.7 mL, convert the volume to liters and use the formula:
\[
\text{Moles} = \text{Molarity} \times \text{Volume in liters}
\]
- Calculate the number of ions by considering Avogadro's number (6.022 × 10\(^{23}\) ions/mole) for each type of ion produced from the dissociation of magnesium chloride.
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