Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 12 of 14**
*How many molecules are in 30.6 moles of CCl₄?*
---
To solve this problem, we will use Avogadro's number, which states that one mole of any substance contains approximately \(6.022 \times 10^{23}\) entities (atoms, molecules, etc.).
Calculation:
1. **Number of Moles Given**: 30.6 moles of CCl₄.
2. **Avogadro’s Number**: \(6.022 \times 10^{23}\) molecules/mole.
3. **Formula**:
\[
\text{Number of molecules} = \text{number of moles} \times \text{Avogadro's number}
\]
4. **Substitute**:
\[
\text{Number of molecules} = 30.6 \times 6.022 \times 10^{23}
\]
This will give you the total number of CCl₄ molecules in 30.6 moles.
Feel free to use a calculator to find the precise answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa04b93a0-8cb6-4c4e-81fa-ab66edf67455%2F8e63d6f5-3db5-4b91-a756-39bcd49f0d43%2Fy9knvj9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 12 of 14**
*How many molecules are in 30.6 moles of CCl₄?*
---
To solve this problem, we will use Avogadro's number, which states that one mole of any substance contains approximately \(6.022 \times 10^{23}\) entities (atoms, molecules, etc.).
Calculation:
1. **Number of Moles Given**: 30.6 moles of CCl₄.
2. **Avogadro’s Number**: \(6.022 \times 10^{23}\) molecules/mole.
3. **Formula**:
\[
\text{Number of molecules} = \text{number of moles} \times \text{Avogadro's number}
\]
4. **Substitute**:
\[
\text{Number of molecules} = 30.6 \times 6.022 \times 10^{23}
\]
This will give you the total number of CCl₄ molecules in 30.6 moles.
Feel free to use a calculator to find the precise answer.
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