**Text:**Use the References to access important values if needed for this question.How many mL of a 0.224 M aqueous solution of manganese(II) sulfate, MnSO₄, must be taken to obtain 15.1 grams of the salt?[Input Box] mL**Explanation:**This is a chemistry question that requires calculating the volume (in milliliters) of a manganese(II) sulfate solution needed to obtain a specific mass of the salt. You would typically use the molarity formula:\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \]To find the moles of MnSO₄ from the given mass, you'd use the molar mass of MnSO₄. Once you have the moles, you can rearrange the formula to solve for the volume in liters, and then convert to milliliters.

Molarity of MnSO4 = 0.224 mol/L ( M = mol/L) Mass of MnSO4 = 15.1 g Molar mass of MnSO4 ,…

Answered: How many mL of a 0.224 M aqueous…

How many mL of a 0.224 M aqueous solution of manganese(II) sulfate, MnSO4, must be taken to obtain 15.1 grams of the salt? mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

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