Fill in all these boxes with correct units. dont fg to put units for each # put down Question 6 of 12How many milliliters of water should a chemist add if they want to prepare an 0.200M aqueous solution with 30.2g of NaCi ? Assume the density of the resultingsolution is the same as the water.STARTING AMOUNTADD FACTORANSWERRESET*( )22.990.0016.022 x 10230.2000.51711.51 x 105151258030.258.4410002.58mLg NaCImol NaCIM NaCIg NaCl/mol Question 5 of 12Determine the amount in grams of KCI that exists in 20.3 g of a solution thatcontains 1.14 | % KCI by massgKeT20.3g solution100g solution0.2319KCI1.14a solution1.1420.39KCI1.14 g KCI20.3 g solution100 g solution= 0.231 g KCIg solution1.14 g KCI20.3 g KCIADD FACTORDELETEANSWERRESET*( )1.141000.01474.5517.80.2316.022 х 10%320.31450123.10.272g KCI%m KCIg solutionmol KCIg KCI/mol

Molarity is defined as the number of moles per liter of the solution. Molarity=Number of moles(1000)Volume in mlCalculate the number of moles. Number of moles = Mass of the substanceMolar mass of the substance Substitute 30.2 g for mass of the substance and 58.44 g for molar mass to calculate the number of moles of NaCl. Number of moles = 30.2 g58.44 g/mol =0.516 mol The number of moles of NaCl is 0.516. Write the expression for molarity. Molarity=Number of molesVolume in L Solve for volume in ml. Volume in L =Number of molesMolarity Substitute 0.516 for number of moles and 0.2 M for molarity to calculate volume. Volume in L =0.516 moles0.2 mol/L =2.583 L Therefore, 2.58 L of water is required.