How many milliliters of a 0.201 M HI solution are needed to reduce 22.0 mL of a0.374 M KMNO, solution according to the following equation:12HI + 2KMNO4 + 2H2SO4· 612 + Mn,SO4 + K,SO, + 8H,OmL

Hydrogen iodide reduces potassium per magnet into manganese(I) sulfate. The equation for the…

Answered: How many milliliters of a 0.201 M HI…

How many milliliters of a 0.201 M HI solution are needed to reduce 22.0 mL of a 0.374 M KMNO4 solution according to the following equation: 12HI + 2KMNO, + 2H,SO, → 61, + Mn,SO4 + K,SO4 + 8H,0 mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

How many milliliters of a 0.201 M HI solution are needed to reduce 22.0 mL of a
0.374 M KMNO, solution according to the following equation:
12HI + 2KMNO4 + 2H2SO4
· 612 + Mn,SO4 + K,SO, + 8H,O
mL

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