How many milliliters of 15.0 M ammonium hydroxide are needed to prepare 175.0 mL of 0.30 M ammonium hydroxide solution?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Problem 4: Dilution Calculation**

*Question:*  
How many milliliters of 15.0 M ammonium hydroxide are needed to prepare 175.0 mL of 0.30 M ammonium hydroxide solution?

*Explanation:*

To solve this problem, we use the formula for dilution, which is:

\[ C_1 \times V_1 = C_2 \times V_2 \]

Where:
- \( C_1 \) is the concentration of the stock solution (15.0 M),
- \( V_1 \) is the volume of the stock solution needed,
- \( C_2 \) is the concentration of the diluted solution (0.30 M),
- \( V_2 \) is the volume of the diluted solution (175.0 mL).

Rearranging the formula to solve for \( V_1 \):

\[ V_1 = \frac{C_2 \times V_2}{C_1} \]

Substitute the given values:

\[ V_1 = \frac{0.30 \times 175.0}{15.0} \]

Calculate \( V_1 \) to find the volume of the concentrated solution required.
Transcribed Image Text:**Problem 4: Dilution Calculation** *Question:* How many milliliters of 15.0 M ammonium hydroxide are needed to prepare 175.0 mL of 0.30 M ammonium hydroxide solution? *Explanation:* To solve this problem, we use the formula for dilution, which is: \[ C_1 \times V_1 = C_2 \times V_2 \] Where: - \( C_1 \) is the concentration of the stock solution (15.0 M), - \( V_1 \) is the volume of the stock solution needed, - \( C_2 \) is the concentration of the diluted solution (0.30 M), - \( V_2 \) is the volume of the diluted solution (175.0 mL). Rearranging the formula to solve for \( V_1 \): \[ V_1 = \frac{C_2 \times V_2}{C_1} \] Substitute the given values: \[ V_1 = \frac{0.30 \times 175.0}{15.0} \] Calculate \( V_1 \) to find the volume of the concentrated solution required.
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