How many liters of oxygen measured at 295 K and 763 torr are consumed in the complete combustion of 1.55 L of C2H4 measured at STP? C2H4 (g) +3 O2 (g) --> 2 CO2 (g) + 2 H20 (1)

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**Combustion of Ethylene: Gas Volume Calculation**

**Problem Statement:**
How many liters of oxygen measured at 295 K and 763 torr are consumed in the complete combustion of 1.55 L of C₂H₄ (ethylene) measured at STP (Standard Temperature and Pressure)?

**Chemical Equation:**
C₂H₄ (g) + 3 O₂ (g) → 2 CO₂ (g) + 2 H₂O (l)

**Explanation:**
This problem requires calculating the volume of oxygen gas needed to completely combust a given volume of ethylene gas, given specific temperature and pressure conditions. The chemical reaction depicts the combustion process of ethylene with oxygen to produce carbon dioxide and water. Note the stoichiometry: 1 mole of C₂H₄ reacts with 3 moles of O₂. You'll need to use the ideal gas law and stoichiometry principles to solve this.
Transcribed Image Text:**Combustion of Ethylene: Gas Volume Calculation** **Problem Statement:** How many liters of oxygen measured at 295 K and 763 torr are consumed in the complete combustion of 1.55 L of C₂H₄ (ethylene) measured at STP (Standard Temperature and Pressure)? **Chemical Equation:** C₂H₄ (g) + 3 O₂ (g) → 2 CO₂ (g) + 2 H₂O (l) **Explanation:** This problem requires calculating the volume of oxygen gas needed to completely combust a given volume of ethylene gas, given specific temperature and pressure conditions. The chemical reaction depicts the combustion process of ethylene with oxygen to produce carbon dioxide and water. Note the stoichiometry: 1 mole of C₂H₄ reacts with 3 moles of O₂. You'll need to use the ideal gas law and stoichiometry principles to solve this.
**Title: Calculating Partial Pressure and Mole Fraction of Oxygen**

Oxygen is collected over water at 22°C and a barometric pressure of 0.985 atm. 

**a) What is the partial pressure of oxygen (in torr)?**

**b) What is the mole fraction of oxygen in the container?**

---

**Note**: To solve part (a), use the fact that water vapor exerts a pressure that depends on temperature. You will need to subtract the vapor pressure of water at 22°C from the total barometric pressure to find the partial pressure of oxygen.

To solve part (b), once the partial pressure of oxygen is found, use it to calculate the mole fraction using the formula:

\[ \text{Mole fraction of oxygen} = \frac{\text{Partial pressure of oxygen}}{\text{Total pressure}} \]
Transcribed Image Text:**Title: Calculating Partial Pressure and Mole Fraction of Oxygen** Oxygen is collected over water at 22°C and a barometric pressure of 0.985 atm. **a) What is the partial pressure of oxygen (in torr)?** **b) What is the mole fraction of oxygen in the container?** --- **Note**: To solve part (a), use the fact that water vapor exerts a pressure that depends on temperature. You will need to subtract the vapor pressure of water at 22°C from the total barometric pressure to find the partial pressure of oxygen. To solve part (b), once the partial pressure of oxygen is found, use it to calculate the mole fraction using the formula: \[ \text{Mole fraction of oxygen} = \frac{\text{Partial pressure of oxygen}}{\text{Total pressure}} \]
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