How many liters of oxygen are necessary for the combustion of 425 g of sulfur, assuming that the reaction occurs at STP?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How many liters of oxygen are necessary for the combustion of 425 g of sulfur, assuming that the reaction occurs at STP?

Expert Solution
Step 1

Chemical equation for the combustion of sulfur is:

S+O2SO2

Hence, 1 mole of oxygen is required to react completely with 1 mole of S.

Number of moles can be calculated by dividing mass by molar mass.

Molar mass of S is 32.065 g/mol.

Hence, number of moles of S = 425 g / (32.065 g/mol)

  = 13.25 mol

Therefore, number of moles of oxygen gas required = 13.25 mol

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