How many liters of 0.305 M K3PO4 solution are necessary to completely react with mL of 0.0184 M NiCl₂ according to the balanced chemical reaction: 187 2 K3PO4(aq) + 3 NiCl₂(aq) → Ni3(PO4)2(S) + 6 KCI(aq)

Q: How many moles of precipitate will be formed when 260.0 mL of 0.200 M NaBr is reacted with excess…

A: Given : Molarity of NaBr = 0.200 M              Volume of solution = 260 mL To find : moles of PbBr2…

Q: What volume, in mL, of 0.364 M Li2CO3 solution is required to react with 53.9 mL of 0.307 M HNO3.…

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Q: What quantity in moles of precipitate will be formed when 45.1 mL of 0.250 M AgNO₃ is reacted with…

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Q: What volume (in mL) of 0.350 M HCl would be required to completely react with 3.90 g of Al in the…

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Q: What quantity in moles of precipitate will be formed when 272.5 mL of 0.400 M NaI is reacted with…

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Q: What volume (in mL) of 0.250 M HCl would be required to completely react with 4.10 g of Al in the…

A: It is well known that by knowing the concentration and number of moles of any substance required for…

Q: How many grams of precipitate are formed when 250.0 mL of 0.110 M ZnCl₂ is mixed with excess KOH in…

A: Zn(OH)2 is the precipitate in this reaction.Molecular mass of Zn(OH)2  = 99.424 g/mol

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO₃)₂ reacts with 33.0 mL of…

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Q: What quantity in moles of precipitate will be formed when 77.1 mL of 0.150 M AgNO3 is reacted with…

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Q: What quantity in moles of precipitate will be formed when 73.7 mL of 0.150 M AgNO₃ is reacted with…

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Q: you begin with 78.2 mL of 0.725 M KCl(aq) solution and mix it with 67 mL of 0.721 M Pb(NO3)2(aq) ,…

A: Given-> Volume of KCl= 78.2 ml Molarity of KCl = 0.725 M Volume of Pb(NO3)2(aq) = 67 ml Molarity…

Q: How many grams of Ag2CO3 will precipitate when excess Na2CO3 solution is added to 45.0 mL of 0.538M…

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Q: What quantity in moles of precipitate will be formed when 168.0 mL of 0.350 M NaCl is reacted with…

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Q: What volume of 0.250 M Na3PO4 is required to precipitate all the lead(II) ions from 190.0 mL of…

A: Molarity is defined as number of mole of solute divide by volume of solution in liter

Q: How many grams of PbBr2 will precipitate when excess AIBr3 solution is added to 51.0 mL of 0.791 M…

A:

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 23.0 mL of…

A: Number of moles of substance=Concentration of substance x Volume of substanceFor…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 31.0 mL of…

A: ZnNO32+2 NaOH→ZnOH2 s+2 NaNO3 aqStength of ZnNO32=20.5x0.700 M1000=0.0143Stength of NaOH=310x0.700…

Q: How many moles of precipitate will be formed when 70.2 mL of 0.150 M AgNO₃ is reacted with excess…

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Q: How many moles of precipitate will be formed when 69.3 mL of 0.300 M AgNO₃ is reacted with excess…

A: Given, 69.3 mL of 0.300 M AgNO₃

Q: How many moles of precipitate will be formed when 200.0 mL of 0.400 M NaI is reacted with excess…

A:

Q: How many grams of Ag₂CO3 will precipitate when excess K₂CO3 solution is added to 65.0 mL of 0.746 M…

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Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO3)2 reacts with 40.0 mL of…

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Q: How many moles of Na₂S will be required to completely react with 41.5 mL of 0.200 M Fe(NO₃)₃? 3 Na₂S…

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Q: If the concentration of a fluoride in a city is drinking water were 0.800 per parts per million how…

A: Given : The concentration of fluoride in parts per million i.e ppm = 0.800 ppm  Since there is no…

Q: What volume (in mL) of 0.300 M HCl would be required to completely react with 3.45 g of Al in the…

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Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Na PO reacts with 62.5 mL of 0.200…

A: Since, Molarity is the number of moles of solute dissolve in one litre of the solution. Thus,

Q: How many milliliters of 0.250 M HNO3 solution can react with 3.25 g of Mg in the following reaction?…

A: Reaction involved : Mg (s) + 2HNO3 (aq) → Mg(NO3)2 (aq) + H2 (g)Mass of Mg = 3.25 gMolarity of HNO3…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO₃)₂ reacts with 22.5 mL of…

A: According law of mass action, the same amount of mass involved in the reaction is formed as a…

Q: How many moles of precipitate will be formed when 112.0 mL of 0.350 M NaCl is reacted with excess…

A: Given reaction:  2 NaCl (aq) + Pb(NO₃)₂ (aq) → PbCl₂ (s) + 2 NaNO₃ (aq) volume of 0.350 M NaCl…

Q: Calculate the volume (in mL) of 0.500 M NA3PO4 solution needed to completely react with 66.73 mL of…

A: Given balanced chemical reaction is: 2Na3PO4(aq) + 3CuCl2(aq) ----> Cu3(PO4)2(s) + 6NaCl(aq)…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO₃)₂ reacts with 34.5 mL of…

A: First calculate moles for both solutions. Then using mol to mol ratio, find out moles of precipitate…

Q: What quantity in moles of precipitate will be formed when 45.6 mL of 0.550 M AgNO3 is reacted with…

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Q: How many liters of 0.305| M K3PO4 solution are necessary to completely react with 187 mL of 0.0184 M…

A: According to the reaction: 2K3PO4(aq)+3 NiCl2(aq)→Ni3(PO42(s) +6 KCl (aq)2 moles of K3PO4 reacts…

Q: How many moles of precipitate will be formed when 74.2 mL of 0.150 M AgNO₃ is reacted with excess…

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Q: Na2CO3(aq)  +  2  HCl(aq)  →   2 NaCl(aq)  +  CO2(g)  +  H2O 0.176 g of sodium carbonate required…

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Q: How many moles of precipitate will be formed when 108.5 mL of 0.200 M NaBr is reacted with excess…

A: Given,Volume of NaBr = 108.5 mL = 0.1085 L       (1 mL =0.001 L)Molarity of NaBr = 0.200 M = 0.2…

Q: What volume (in mL) of 0.400 M HCl would be required to completely react with 3.70 g of Al in the…

A: Molar mass of Al = 26.98 g/mol. Mass of Al = 3.70 g. Number of moles of Al is calculated as follows:…

Q: A chemist performs a gravimetric analysis. The chemist combines 1.00 L of 2.00 M AGNO, (ag) with…

A: Given: Concentration of AgNO3 = 2M Concentration of NaCl = 4M Volume of AgNO3 = 1 L Volume of NaCl =…

Q: Copper(II) ions can be precipitated as copper(II) carbonate: CuSO4(aq) + Na2CO3(aq) → CuCO3(s) +…

A: Calculate firstly millimoles of CuSO4 , then use the stoichiometric calculations to find the weight…

Q: How many moles of precipitate will be formed when 85.7 mL of 0.150 M AgNO₃ is reacted with excess…

A:

Q: What quantity in moles of precipitate will be formed when 100.0 mL of 2.00 M NaI is reacted with…

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Q: What quantity in moles of Na₂S will be required to completely react with 77.0 mL of 0.200 M…

A: Given: Volume of Fe(NO3)3 solution = 77 ml Or volume of Fe(NO3)3 solution = 77 × 10-3 L And…

Q: Based on the balanced chemical equation shown below, determine the concentration (M) of Fe2+(aq) if…

A: Volume of Fe2+ = 40.00 ml = V1Volume of BrO3- = 43.47 ml = V2Molarity of BrO3- = 0.125 M = M2

Q: What quantity in moles of precipitate will be formed when 56.4 mL of 0.300 M AgNO3 is reacted with…

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Q: What volume, in L, of 0.204 M NiCl2 solution is required to produce 69.9 g of precipitate.…

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Q: What volume, in mL, of 0.249 M Li2CO3 solution is required to react with 65.4 mL of 0.422 M HNO3.…

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.