Hello, I need help with this equation. Please show me how to organize the equation, just EXACT like the screenshot. I knew the final result is 0.00752 LThank you! How many liters of 0.305 M KPO. solution are necessary to completely react with187mL of 0.0184 M NICI according to the balanced chemical reaction:K.РО(аq) +3NiCl:(aq) → Nis(PO.):(s) +6.KCI(aq)187mL NiCl22LKPO4X0.0184L NIC.3motNICT0.305mol KPO40.0184 mol NiC.187 mL NiCl22L KPO4L NICl23 mol NiCl20.305 mol KaPO4ADD FACTORDELETEANSWERRESET*( )X0.011316.022 x 10230.30518710000.00136.0.003760.007520.01847.52mL KsPO4M KPO4M NICI2g KsPO4LKPO4mol KPO4mol NiCl2mL NICI2L NICI2g NICI22.

Given information, Molarity of K3PO4 = 0.305 M Molarity of NiCl2 = 0.0184 M Volume of NiCl2 = 187 mL…

How many liters of 0.305 M K.PO. solution are necessary to completely react with 187 mL of 0.0184 M NICI according to the balanced chemical reaction: KPO:(aq) + 3 NICI:(aq) Nis(PO.):(s) + KCI(aq) molNICIE 187 mL NICI2 2 LKPO. 0.0184 L NICI2 3 mo-NICIE 0.305 mol KPO. 0.0184 mol NiCl2 187 mL NICI2 2L KPO4 L NICI: 3 mol NiCl2 0.305 mol KPO. ADD FACTOR DELETE ANSWER RESET *( ) 0.0113 6.022 x 1023 0.305 187 2 1000 0.001 3 6 0.00376 0.00752 0.0184 7.52 mL K.PO. M К.РО M NICI2 g KPO. LKPO. mol KPO. mol NiCl2 mL NICI2 L NICI g NiCl2

How many liters of 0.305 M K.PO. solution are necessary to completely react with 187 mL of 0.0184 M NICI according to the balanced chemical reaction: KPO:(aq) + 3 NICI:(aq) Nis(PO.):(s) + KCI(aq) molNICIE 187 mL NICI2 2 LKPO. 0.0184 L NICI2 3 mo-NICIE 0.305 mol KPO. 0.0184 mol NiCl2 187 mL NICI2 2L KPO4 L NICI: 3 mol NiCl2 0.305 mol KPO. ADD FACTOR DELETE ANSWER RESET *( ) 0.0113 6.022 x 1023 0.305 187 2 1000 0.001 3 6 0.00376 0.00752 0.0184 7.52 mL K.PO. M К.РО M NICI2 g KPO. LKPO. mol KPO. mol NiCl2 mL NICI2 L NICI g NiCl2

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 134AP

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