Is this correct and complete based on the information and data? Dốt plot of hðurs on Sočlal MedlaQuestion 2: How many hours a day do you spend on social media?The graphs and charts below represent a survey using qualitative data. In thespace provided below the last graph of question 2, please state a conclusion forthese graphs. This should include answering the following.What is your mean and median?Based on this information is the graph skewed?Are there any outliers? State the value of the outliers or state that no outlierswere noted.What other outcomes did you find interesting from these graphs/charts.Minimum1StatisticsMaximum4HoursPercentiles251.00NValid30331.00Missing502.00Mean1.85Hours672.00Median2.00752.25Mode1Std. Deviation863RangeHoursCumulativeFrequencyPercentValid PercentPercentValid11240.040.040.013.33.343.31033.333.376.7Hours320.020.096.713.33.3100.0Total30100.0100.01.01.52.53.03.54.0Box Plot for hours of Social Media per day Part B Conclusions:Based on the above results of the included data and graphics.1. Mean and MedianMean: 1.85Median: 2.002. The mean is less than median and we can see that it is negativelyskewed distribution. Based on that information we can perceive that thedata of the graph is elongated towards the left side. Therefore, thedistribution is said to negatively skewed. The median is greater thanmean skewed left.3. Potential outliers are value that lie above the upper fence or below thelower fence of the sample set.Upper fence = 4.1250Lower Fence= 0.8750Hence there is no less that (-0.8750) and not more than (4.1250)meaning no outliers are present.From graph we see that is goes from upper to lower of left skewed thatmeans negatively skewed distribution.4. Here the box plot spread of all data.From the box plot we see that box length's interquartile range is 1.25minimum is 1 and maximum is 4. Then the lower quartile is 1 and upperquartile is 2.25. Median is 2.

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Description: Is this correct and complete based on the information and data? Dốt plot of hðurs on Sočlal MedlaQuestion 2: How many hours a day do you spend on social media?The graphs and charts below represent a survey using qualitative data. In thespace provided

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How many hours a day do you spend on social media? and charts below represent a survey using qualitative data. In the ded below the last graph of question 2, please state a conclusion for as. This should include answering the following. ar mean and median? mis information is the graph skewed? ny outliers? State the value of the outliers or state that no outliers

How many hours a day do you spend on social media? and charts below represent a survey using qualitative data. In the ded below the last graph of question 2, please state a conclusion for as. This should include answering the following. ar mean and median? mis information is the graph skewed? ny outliers? State the value of the outliers or state that no outliers

MATLAB: An Introduction with Applications

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Publisher:Amos Gilat

Chapter1: Starting With Matlab

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Concept explainers

Inverse Normal Distribution

The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.

Mean, Median, Mode

It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.

Z-Scores

A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.

Topic Video

Question

Is this correct and complete based on the information and data?

Part B Conclusions:
Based on the above results of the included data and graphics.
1. Mean and Median
Mean: 1.85
Median: 2.00
2. The mean is less than median and we can see that it is negatively
skewed distribution. Based on that information we can perceive that the
data of the graph is elongated towards the left side. Therefore, the
distribution is said to negatively skewed. The median is greater than
mean skewed left.
3. Potential outliers are value that lie above the upper fence or below the
lower fence of the sample set.
Upper fence = 4.1250
Lower Fence= 0.8750
Hence there is no less that (-0.8750) and not more than (4.1250)
meaning no outliers are present.
From graph we see that is goes from upper to lower of left skewed that
means negatively skewed distribution.
4. Here the box plot spread of all data.
From the box plot we see that box length's interquartile range is 1.25
minimum is 1 and maximum is 4. Then the lower quartile is 1 and upper
quartile is 2.25. Median is 2.

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