How many grams of solute are present in 885 mL of 0.640 M KBr? mass of solute: g

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Question:** How many grams of solute are present in 885 mL of 0.640 M KBr?

**Answer Field:**  
mass of solute: \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ g 

**Explanation:**

To calculate the mass of the solute, potassium bromide (KBr), in the solution, you need to follow these steps:

1. **Convert Volume to Liters:**
   - 885 mL = 0.885 L

2. **Use the Molarity Formula:**
   - Molarity (M) = moles of solute / liters of solution

3. **Calculate Moles of Solute:**
   - Moles of KBr = Molarity × Volume in liters
   - Moles of KBr = 0.640 mol/L × 0.885 L = 0.5664 mol

4. **Calculate Mass of Solute:**
   - Use the molar mass of KBr (approximately 119.00 g/mol)
   - Mass = moles × molar mass
   - Mass = 0.5664 mol × 119.00 g/mol = 67.3968 g

Therefore, there are approximately 67.40 grams of KBr in the solution.
Transcribed Image Text:**Question:** How many grams of solute are present in 885 mL of 0.640 M KBr? **Answer Field:** mass of solute: \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ g **Explanation:** To calculate the mass of the solute, potassium bromide (KBr), in the solution, you need to follow these steps: 1. **Convert Volume to Liters:** - 885 mL = 0.885 L 2. **Use the Molarity Formula:** - Molarity (M) = moles of solute / liters of solution 3. **Calculate Moles of Solute:** - Moles of KBr = Molarity × Volume in liters - Moles of KBr = 0.640 mol/L × 0.885 L = 0.5664 mol 4. **Calculate Mass of Solute:** - Use the molar mass of KBr (approximately 119.00 g/mol) - Mass = moles × molar mass - Mass = 0.5664 mol × 119.00 g/mol = 67.3968 g Therefore, there are approximately 67.40 grams of KBr in the solution.
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