Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Question:** How many grams of solute are present in 885 mL of 0.640 M KBr?
**Answer Field:**
mass of solute: \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ g
**Explanation:**
To calculate the mass of the solute, potassium bromide (KBr), in the solution, you need to follow these steps:
1. **Convert Volume to Liters:**
- 885 mL = 0.885 L
2. **Use the Molarity Formula:**
- Molarity (M) = moles of solute / liters of solution
3. **Calculate Moles of Solute:**
- Moles of KBr = Molarity × Volume in liters
- Moles of KBr = 0.640 mol/L × 0.885 L = 0.5664 mol
4. **Calculate Mass of Solute:**
- Use the molar mass of KBr (approximately 119.00 g/mol)
- Mass = moles × molar mass
- Mass = 0.5664 mol × 119.00 g/mol = 67.3968 g
Therefore, there are approximately 67.40 grams of KBr in the solution.
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