I need the last part. Activity coefficients can be found in the other picture. TABLE 12-1 Activity coefficients for aqueous solutions at 25°CIonsize(a, pm)lon(CH3)2CHCO₂, (C₂H₂)4N*ONCH0 (CH,ANH", CH,OC H CO,Li*,C%H,CO2, HỌC,H,CO2, CICH,CO2, C%H_CH,COz,CH,=CHCH,CO2, (CH3),CHCH,CO2,(CH,CH,)N*, (C,H,),NHCLCHCOCI,CCO₂, (CH₂CH₂)₂NH". (C₂H₂)NH;Charge = ±1Na+, CdCI+, CIO2, 103, HCO3, H₂PO4, HSO3, H2₂ASO4,Co(NH3)4(NO₂)2, CH,CO₂, CICH₂CO₂, (CH₂)4N*,(CH,CH,),NH, HẠNCH,CO;*H_NCH-CO,H, (CHÍNH, CHÍCHÍNH:OH, F, SCN, OCN, HS, CIO, CIO4, BrO3, 104, MnO4,HCO₂, H₂citrate, CH₂NH, (CH3)₂NH₂KC Br.I.CN, NO₂, NORb, Cs*, NH, TI, AgMg²+, Be*CH,(CH,CH,COz ), (CH,CH,CH,CO5 )Ca²*, Cu, Zn²*, Sn²*, Mn, Fe, Ni, Co²¹, C₂H₂(CO₂).H-C(CH₂CO3)₂(CH₂CH₂CO3)2Charge = ±2Sr+, Ba²+, Cd²+, Hg2+, S2, S₂O, WO, H₂C(CO₂)2.(CH₂CO₂)2, (CHOHCO₂)2lanthanides"Pb², CO SO Moo, Co(NH₂),C1, Fe(CN) NO. C₂0.HeitrateHg. So.S₂0, S₂02, S₂0, Seo, Cro?", HPOThZ¹ Ce, SnFe(CN)a. Lanthanides are elements 57-71 in the periodic table.SOURCE: J. Kielland, J. Am. Chem. Soc. 1937, 59, 1675.Charge ±3citrate 3-FO FUCNK CẠNH CNH) CÁNH.HO:Charge = ±4900800700450400600 0.965 0.929 0.907 0.835 0.80500 0.964 0.928 0.904 0.83 0.79350300250800700500450400900500400Ionic strength (u, M)0.001 0.005 0.01 0.05 0.11 1000.967 0.933 0.914 0.86 0.830.966 0.931 0.912 0.85 0.820.965 0.930 0909 0.845 0.81600 0.870 0.749 0.675 0.485 0.4055000.964 0.928 0.902 0.82 0.7750.964 0.927 0.901 0815 0.770.964 0.926 0.900 0.81 0.760.964 0.925 0.899 0.805 0.7550.964 0.924 0.898 0.80 0.750.872 0.755 0.69 0.52 0.450.872 0.755 0.685 0.50 0.4250.868 0.744 0.67 0.465 0.380.867 0.742 0.665 0.455 0.370.867 0.740 0.660 0.445 0.3550.738 0.54 0.445 0.245 0.180.728 0.51 0.405 0.18 0.1150.725 0.505 0.395 0.16 0.0950.588 0.35 0.255 0.10 0.0650.57 0.31 0.20 0.048 0.021269 The solubility product constant for PbI₂ is 7.90×10-⁹ at 25 °C. What is the molar concentration of I ions in a saturated solution of PbI₂? Assume an ideal solution at 25 °C.2.51×10-3You are correct.Your receipt no. is 161-993 ⒸPrevious TriesHow many grams of PbI₂ (461.0 g/mol) can be dissolved in 600 mL of pure water at 25 °C?3.47x10-1You are correct.Your receipt no. is 161-9519 ??Previous TriesHow many grams of PbI₂ can be dissolved in 600 mL of a 0.100 M KI solution at 25 °C? Use activities for this calculation. Activity coefficients can be found in Table 12-1 of your textbook.2.19E-4Submit Answer You have entered that answer before Incorrect. TriesPrevious Tries

Given:Volume of KI solution = 600 mLConcentration of KI solution = 0.100 MTemperature = 25oCActivity coefficients Pb2+ = 0.37I- = 0.755A mole is a fundamental unit used to measure the amount of a substance. It is described as the quantity of a substance that includes the same number of atoms as there are in exactly 12 g of pure carbon-12 isotope.Mole is obtained by dividing the given mass of a substance by its molar mass.To calculate the molar concentration of I− ions in a saturated solution of PbI2, use the solubility product constant (Ksp) and the stoichiometry of the dissociation of PbI2 in water.The balanced equation for the dissociation of PbI2 is:The Ksp expression for this equilibrium is:....(1)Now substitute the values in equation and we get:Now calculate the number of moles of PbI2:Now calculate the mass of PbI2:Therefore, the mass of PbI2 is 0.00104 g.