How many grams of PbBr2 will precipitate when excess NaBr solution is added to 59.0 mL of 0.751 M Pb(NO03)2 solution? Pb(NO3)2(aq) + 2NaBr(aq) PbBr2(s) + 2NaNO3(aq)
How many grams of PbBr2 will precipitate when excess NaBr solution is added to 59.0 mL of 0.751 M Pb(NO03)2 solution? Pb(NO3)2(aq) + 2NaBr(aq) PbBr2(s) + 2NaNO3(aq)
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Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.81QP: A 8.50 g sample of KCl is dissolved in 66.0 mL of water. The resulting solution is then added to...
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Transcribed Image Text:How many grams of PbBr, will precipitate when excess NaBr solution is added to 59.0 mL of 0.751 M Pb(NO,)2 solution?
Pb(NO3)2(aq) + 2NaBr(aq)
→PBB12(s) + 2NaNO3(aq)
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As the NaBr is present in excess amount the yield of reaction is depend upon the moles of Pb(NO3)2 .
So first we have to calculate the moles of Pb(NO3)2 .
Form the moles of Pb(NO3)2 and the Balanced chemical equation we get the moles of PbBr2 produced in the reaction .
Form the moles of PbBr2 we can calculate the mass of PbBr2 precipitated in the reaction .
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