Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Grams of Cl<sub>2</sub>: 259.4 g Cl<sub>2</sub>**
In this section, we are given a numerical value representing the amount of chlorine gas (Cl<sub>2</sub>) in grams. The specific quantity provided is 259.4 grams, as indicated in the form-like text box.
This value is essential for various calculations and chemical reactions involving chlorine gas. It is crucial to accurately measure and work with this quantity to ensure correct results.
By understanding these measurements, students can effectively engage in laboratory activities and theoretical exercises related to chemistry and the behavior of chlorine gas in different contexts.
There are no graphs or diagrams associated with this text to analyze further.
![# Determining the Amount of Cl₂ Needed to Form AlCl₃
## Problem Statement:
**Question:** How many grams of Cl₂ are needed to form 81.3 g of AlCl₃?
**Chemical Equation:**
\[ 2 \text{Al}(s) + 3 \text{Cl}_2(g) \rightarrow 2 \text{AlCl}_3(s) \]
## Step-by-Step Solution:
### Step 1: Strategy for Solving the Problem
To solve this problem, follow these steps:
1. Convert grams of AlCl₃ to moles of AlCl₃.
2. Use the stoichiometry of the chemical reaction to convert moles of AlCl₃ to moles of Cl₂.
3. Convert moles of Cl₂ to grams of Cl₂.
**Diagram:**
\[ \text{grams AlCl₃} \rightarrow \text{moles AlCl₃} \rightarrow \text{moles Cl₂} \rightarrow \text{grams Cl₂} \]
**Answer Bank:**
- grams Cl₂
- moles Al
- grams AlCl₃
- grams Al
The correct labels for the diagram:
\[
\text{grams AlCl₃} \rightarrow \text{moles AlCl₃} \rightarrow \text{moles Cl₂} \rightarrow \text{grams Cl₂}
\]
### Step 2: Show the Conversions Required
1. **Convert grams of AlCl₃ to moles of AlCl₃:**
\[
81.3 \text{ g AlCl}_3 \times \left( \frac{1 \text{ mole AlCl}_3}{133.33 \text{ g AlCl}_3} \right)
\]
2. **Convert moles of AlCl₃ to moles of Cl₂ using the mole ratio from the balanced equation:**
\[
\times \left( \frac{3 \text{ moles Cl}_2}{2 \text{ moles AlCl}_3} \right)
\]
3. **Convert moles of Cl₂ to grams of Cl₂:**
\[
\times \left( \frac{70.90 \text{ g Cl}_2}{1 \text{ mole Cl}_2} \right)
\]
Combining all steps:
\[
81](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b52cd77-b3d2-4b5d-8903-b23362bef087%2Fd2832ae5-58c3-47eb-97ab-93ff933faa43%2F5o6nhcr_processed.png&w=3840&q=75)
Transcribed Image Text:# Determining the Amount of Cl₂ Needed to Form AlCl₃
## Problem Statement:
**Question:** How many grams of Cl₂ are needed to form 81.3 g of AlCl₃?
**Chemical Equation:**
\[ 2 \text{Al}(s) + 3 \text{Cl}_2(g) \rightarrow 2 \text{AlCl}_3(s) \]
## Step-by-Step Solution:
### Step 1: Strategy for Solving the Problem
To solve this problem, follow these steps:
1. Convert grams of AlCl₃ to moles of AlCl₃.
2. Use the stoichiometry of the chemical reaction to convert moles of AlCl₃ to moles of Cl₂.
3. Convert moles of Cl₂ to grams of Cl₂.
**Diagram:**
\[ \text{grams AlCl₃} \rightarrow \text{moles AlCl₃} \rightarrow \text{moles Cl₂} \rightarrow \text{grams Cl₂} \]
**Answer Bank:**
- grams Cl₂
- moles Al
- grams AlCl₃
- grams Al
The correct labels for the diagram:
\[
\text{grams AlCl₃} \rightarrow \text{moles AlCl₃} \rightarrow \text{moles Cl₂} \rightarrow \text{grams Cl₂}
\]
### Step 2: Show the Conversions Required
1. **Convert grams of AlCl₃ to moles of AlCl₃:**
\[
81.3 \text{ g AlCl}_3 \times \left( \frac{1 \text{ mole AlCl}_3}{133.33 \text{ g AlCl}_3} \right)
\]
2. **Convert moles of AlCl₃ to moles of Cl₂ using the mole ratio from the balanced equation:**
\[
\times \left( \frac{3 \text{ moles Cl}_2}{2 \text{ moles AlCl}_3} \right)
\]
3. **Convert moles of Cl₂ to grams of Cl₂:**
\[
\times \left( \frac{70.90 \text{ g Cl}_2}{1 \text{ mole Cl}_2} \right)
\]
Combining all steps:
\[
81
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