Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Determining the Amount of C<sub>6</sub>H<sub>6</sub> Decomposition
#### Problem Statement:
How many grams of C<sub>6</sub>H<sub>6</sub> must decompose according to the following chemical equation to transfer 430 kJ of heat?
#### Given Chemical Equation:
\[ \text{C}_6\text{H}_6(l) \rightarrow 3 \, \text{C}_2\text{H}_2(g) \]
\[\Delta H = 630 \, \text{kJ} \]
#### Process:
The solution involves using a conversion factor method to find the required amount. The steps involve using the provided conversion factors in blue buttons to input into the equation.
#### Equation Layout:
To solve this, set up the equation in the provided format.
\[
\text{Starting Amount} \times \left( \frac{\text{Conversion Factor}}{\text{Conversion Factor}} \right)
\]
### Components:
1. **Starting Amount**: This is the initial value you start with. In our case, it’s the energy in kJ that needs to be transferred, which is 430 kJ.
2. **Conversion Factors**: These include quantities from the equation or other constants that help us convert from one unit to another.
#### Detailed Breakdown:
1. **Starting Amount**:
\[
430 \, \text{kJ}
\]
2. **Conversion Factors** (selected from bottom buttons):
- From the equation: 630 kJ of heat per 1 mole of C<sub>6</sub>H<sub>6</sub>.
- Molar mass of C<sub>6</sub>H<sub>6</sub>: 78.12 g/mol
#### Factor Setup:
We need to convert heat (kJ) to grams of C<sub>6</sub>H<sub>6</sub> decomposed:
\[
430 \, \text{kJ} \times \left( \frac{1 \text{ mole C}_6\text{H}_6}{630 \, \text{kJ}} \right) \times \left( \frac{78.12 \, \text{g C}_6\text{H}_6}{1 \text{ mole C}_6\text{H}_6} \](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb05998c5-9aa7-4463-a9df-7f7abe049b9d%2Fd7033c2e-f25b-44ee-bc85-17a42f7c22c7%2Fe8yajd7h_processed.png&w=3840&q=75)
Transcribed Image Text:### Determining the Amount of C<sub>6</sub>H<sub>6</sub> Decomposition
#### Problem Statement:
How many grams of C<sub>6</sub>H<sub>6</sub> must decompose according to the following chemical equation to transfer 430 kJ of heat?
#### Given Chemical Equation:
\[ \text{C}_6\text{H}_6(l) \rightarrow 3 \, \text{C}_2\text{H}_2(g) \]
\[\Delta H = 630 \, \text{kJ} \]
#### Process:
The solution involves using a conversion factor method to find the required amount. The steps involve using the provided conversion factors in blue buttons to input into the equation.
#### Equation Layout:
To solve this, set up the equation in the provided format.
\[
\text{Starting Amount} \times \left( \frac{\text{Conversion Factor}}{\text{Conversion Factor}} \right)
\]
### Components:
1. **Starting Amount**: This is the initial value you start with. In our case, it’s the energy in kJ that needs to be transferred, which is 430 kJ.
2. **Conversion Factors**: These include quantities from the equation or other constants that help us convert from one unit to another.
#### Detailed Breakdown:
1. **Starting Amount**:
\[
430 \, \text{kJ}
\]
2. **Conversion Factors** (selected from bottom buttons):
- From the equation: 630 kJ of heat per 1 mole of C<sub>6</sub>H<sub>6</sub>.
- Molar mass of C<sub>6</sub>H<sub>6</sub>: 78.12 g/mol
#### Factor Setup:
We need to convert heat (kJ) to grams of C<sub>6</sub>H<sub>6</sub> decomposed:
\[
430 \, \text{kJ} \times \left( \frac{1 \text{ mole C}_6\text{H}_6}{630 \, \text{kJ}} \right) \times \left( \frac{78.12 \, \text{g C}_6\text{H}_6}{1 \text{ mole C}_6\text{H}_6} \
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