: How many grams of carbon dioxide are produced when 20.0 g acetylene (C₂H₂) is burned? (d

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10 N
4. Solving a mass-to-mass problem requires the four steps listed below. The equations in the boxes
show how the four steps are used to solve an example problem. After you have studied the example,
solve the problems below, using the four steps.
Example problem: How many grams of carbon dioxide are produced when 20.0 g acetylene (C₂H₂) is burned?
Step 1 Write a balanced chemical equation for the reaction.
Step 2 Determine the number of moles of the known substance, using
mass-to-mole conversion.
20.0g₂x
ambubong bus aime=0.768 mol C₂H₂
Step 3 Determine the number of moles of the unknown substance, using
mole-to-mole conversion.
Solution
2C₂H2(g) + 5O2(g) → 4CO2(g) + 2H₂O(g)
1 mol C₂H₂W (b
26.04g CH₂
Step 4 Determine the mass of the unknown substance, using mole-to-mass
conversion.
dans avollot and consups sdi lameldong smil ovie
stsigmomoldongodi ovloz of od ustadt oites slo
sota W
0.768 mol H₂x;
1.54 mol CO₂
1.54 molox
nsgyxo bas obixorbyd musiboa a
1101BW
foot or assiqot notipo=67.8 g CO₂
(2) 0+ (2)HOM (DOHS - (₂) 0
ob woll (o
Yongrtion
4 mol CO₂
2 mol H₂
44.01 g CO₂oileupo adi
Imoleo, pored
snovolfot od ang
2
Transcribed Image Text:10 N 4. Solving a mass-to-mass problem requires the four steps listed below. The equations in the boxes show how the four steps are used to solve an example problem. After you have studied the example, solve the problems below, using the four steps. Example problem: How many grams of carbon dioxide are produced when 20.0 g acetylene (C₂H₂) is burned? Step 1 Write a balanced chemical equation for the reaction. Step 2 Determine the number of moles of the known substance, using mass-to-mole conversion. 20.0g₂x ambubong bus aime=0.768 mol C₂H₂ Step 3 Determine the number of moles of the unknown substance, using mole-to-mole conversion. Solution 2C₂H2(g) + 5O2(g) → 4CO2(g) + 2H₂O(g) 1 mol C₂H₂W (b 26.04g CH₂ Step 4 Determine the mass of the unknown substance, using mole-to-mass conversion. dans avollot and consups sdi lameldong smil ovie stsigmomoldongodi ovloz of od ustadt oites slo sota W 0.768 mol H₂x; 1.54 mol CO₂ 1.54 molox nsgyxo bas obixorbyd musiboa a 1101BW foot or assiqot notipo=67.8 g CO₂ (2) 0+ (2)HOM (DOHS - (₂) 0 ob woll (o Yongrtion 4 mol CO₂ 2 mol H₂ 44.01 g CO₂oileupo adi Imoleo, pored snovolfot od ang 2
Expert Solution
Step 1

Answer:

acetylene is a hydrocarbon and when it is burned in presence of oxygen it forms CO2 and water produces lots of energy.

Given data:

mC2H2=20.0g

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