How many grams of Al203 are formed from 15.0L of 02 at 97.3 kPa and 21 degrees C according to the following equation: Al + 02 » Al203 Given L, start with

Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter13: Gases
Section: Chapter Questions
Problem 65QAP
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Find the mistake. A student calculated their answer to a gas law problem as shown in the image below. Their
answer is incorrect. Review their work and find the mistake the student made in their calculation. The question
is typed in the upper left corner.
Hint: There is only 1 step that is incorrect and the issue IS NOT related to significant figures!
Click here for the Gas Laws Formula Sheet.
Click here for the Periodic Table.
How many grams of
Al203 are formed
from 15.0L of 02 at
97.3 kPa and 21
degrees C according
to the following
equation:
Al + 02 → Al203
G: V:(5.0L02 T= 21°C+ 273=294K,
P=97.3 le Pa, R=8,314 L·bla
ひ-n Cmoe)
E:PV=n RT→ n=PV
9 7,3 kPa (15,OK) RT
8.う144efa (aat
mol. K
S: n=
Given L,
start with
S n=0.597mol O2
Ideal Gas
Law.
o597moll!molAT203
| 101.969A1203
Al203
Transcribed Image Text:Find the mistake. A student calculated their answer to a gas law problem as shown in the image below. Their answer is incorrect. Review their work and find the mistake the student made in their calculation. The question is typed in the upper left corner. Hint: There is only 1 step that is incorrect and the issue IS NOT related to significant figures! Click here for the Gas Laws Formula Sheet. Click here for the Periodic Table. How many grams of Al203 are formed from 15.0L of 02 at 97.3 kPa and 21 degrees C according to the following equation: Al + 02 → Al203 G: V:(5.0L02 T= 21°C+ 273=294K, P=97.3 le Pa, R=8,314 L·bla ひ-n Cmoe) E:PV=n RT→ n=PV 9 7,3 kPa (15,OK) RT 8.う144efa (aat mol. K S: n= Given L, start with S n=0.597mol O2 Ideal Gas Law. o597moll!molAT203 | 101.969A1203 Al203
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