How many gallons of a 80% antifreeze solution Strengthmust be mixed with 70 gallons of 25%antifreeze to get a mixture that is 70%antifreeze? Use the six-step method.You needgallons.(Round to the nearest whole number.)80%25%70%Gallons ofSolutionsX70x + 70Gallons ofAntifreeze

Let, x gallon of antifreeze solution is mixed with 70 gallons of antifreeze solution. Then, in the…

Answered: How many gallons of a 80% antifreeze…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Related questions

Question

How many gallons of a 80% antifreeze solution Strength
must be mixed with 70 gallons of 25%
antifreeze to get a mixture that is 70%
antifreeze? Use the six-step method.
You need
gallons.
(Round to the nearest whole number.)
80%
25%
70%
Gallons of
Solutions
X
70
x + 70
Gallons of
Antifreeze

Expert Solution

Step 1: Description of given data

Let, x gallon of $80 percent sign$ antifreeze solution is mixed with 70 gallons of $25 percent sign$ antifreeze solution.

Then, in the first solution, amount of antifreeze. $equals space x space cross times space 80 percent sign space equals space 0.8 x space g a l l o n s$ .

In the second solution, amount of antifreeze. $equals space 70 space cross times space 25 percent sign space equals space 17.5 space g a l l o n s$ .

So, total quantity of solution. $equals space left parenthesis 70 space plus space x right parenthesis space g a l l o n s$ .

Total quantity of antifreeze $equals space left parenthesis 0.8 x space plus space 17.5 right parenthesis space g a l l o n$

So, concentration of antifreeze in new solution $equals space fraction numerator left parenthesis 0.8 x space plus space 17.5 right parenthesis over denominator left parenthesis 70 space plus space x right parenthesis end fraction cross times 100 space percent sign$