How many electrons does 58 Ni2+ have?
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- A resistor the flow of electrons. absorbs O increases O restricts O dividesMass of electron m₀ : 9.1 × 10⁻³¹kg Avogadro number N₂ : 6.02 × 10²³ Charge of electron ℯ : 1.6 × 10⁻¹⁹ C 1 ℯV = 1.6 × 10⁻¹⁹ J Boltzman costant k₃ : 1.38 × 10⁻²³ J/K = 8.6 × 10⁻⁵ ℯV/K R = 8.314 J/K·mol Q. The equilibrium interatomic spacing and melting point of sodium halide are as follows. Explain the reasons for the observed trend. NaF NaCI NaBr NaI interval(nm) 0.23 0.28 0.29 0.32 meltingpoint(℃) 988 801 740 660None
- A monatomic ion has a charge of +2. The nucleus of the ion has a mass number of 86. The number of neutrons in the nucleus is 1.26 times that of the number of protons. How many electrons and what is the element?Problem 3: A 1.2 g wire has a density of 2.7 g/cm3 and a resistivity of 2.7 × 10−8 Ωm. The wire has a resistance of 15 Ω. a) How long is the wire? b) The wire is made up of atoms with valence 1 and molar mass 26.98 g/mol. What is the drift speed of the electrons when there is a voltage drop of 30 V across the wire?St. John's University - My App X A ALEKS - Iffat Khan G how many valence electrons in x + i www-awn.aleks.com/alekscgi/x/lsl.exe/1o_u-lgNslkr7j8P3jH-lijkPWvZoZLqkt1FLIq7wcPWKzBYGfE9IMFjNG0dB_IllkUmxjvdZ3p44elzs8GVwNxjbe5NR20.. * O MEASUREMENT Setting up the solution to a basic quantitative problem The electric field strength between the plates of a simple air capacitor is equal to the voltage across the plates divided by the distance between them. When a voltage of 94.8 V is put across the plates of such a capacitor an electric field strength of 2.3 kV is measured. cm Write an equation that will let you calculate the distance d between the plates. Your equation should contain only symbols. Be sure you define each symbol. Your equation: d =| Definitions of your symbols: kV D = 2.3 cm = 94,8 V Explanation Check © 2021 McGraw-Hill Education. All Riahts Reserved. Terms of Use I Privacy étv II