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How many degrees of unsaturation are represented by the formula C7H1303N2B13? 1 3. 4

How many degrees of unsaturation are represented by the formula C7H1303N2B13? 1 3. 4

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:** How many degrees of unsaturation are represented by the formula C₇H₁₃O₃N₂Br₃? **Options:** - 0 - 1 - 2 - 3 (Correct answer highlighted) - 4 **Explanation for Educational Purposes:** Degrees of unsaturation, also known as the index of hydrogen deficiency, is a structural feature that offers information about the number of rings and/or multiple bonds present in a compound. It is calculated using the formula: \[ \text{Degrees of Unsaturation} = \frac{2C + 2 + N - H - X}{2} \] where: - \( C \) is the number of carbons, - \( N \) is the number of nitrogens, - \( H \) is the number of hydrogens, - \( X \) is the number of halogens (in this case, bromine). For the formula C₇H₁₃O₃N₂Br₃: \[ \text{Degrees of Unsaturation} = \frac{2(7) + 2 + 2 - 13 - 3}{2} = \frac{14 + 2 + 2 - 13 - 3}{2} = \frac{2}{2} = 1 \] The correct degree of unsaturation should be calculated as 1, indicating either one ring or one double bond. The highlighted option "3" seems to be an error if using the stated calculation method.
Transcribed Image Text:**Question:** How many degrees of unsaturation are represented by the formula C₇H₁₃O₃N₂Br₃? **Options:** - 0 - 1 - 2 - 3 (Correct answer highlighted) - 4 **Explanation for Educational Purposes:** Degrees of unsaturation, also known as the index of hydrogen deficiency, is a structural feature that offers information about the number of rings and/or multiple bonds present in a compound. It is calculated using the formula: \[ \text{Degrees of Unsaturation} = \frac{2C + 2 + N - H - X}{2} \] where: - \( C \) is the number of carbons, - \( N \) is the number of nitrogens, - \( H \) is the number of hydrogens, - \( X \) is the number of halogens (in this case, bromine). For the formula C₇H₁₃O₃N₂Br₃: \[ \text{Degrees of Unsaturation} = \frac{2(7) + 2 + 2 - 13 - 3}{2} = \frac{14 + 2 + 2 - 13 - 3}{2} = \frac{2}{2} = 1 \] The correct degree of unsaturation should be calculated as 1, indicating either one ring or one double bond. The highlighted option "3" seems to be an error if using the stated calculation method.
Expert Solution
Step 1

Given formula is, 

C7H13O3N2Br3 

Number of carbon atoms = 7 

Number of hydrogen atoms = 13 

Number of nitrogen atoms = 2 

Number of bromine atoms = 3

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