How many computers? In a simple random sample of 185 households, the sample mean number of personal computers was 2. Assume the populationstandard deviation is = 0.52,Part: 0 / 4Part 1 of 4(a) Construct a 95% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places.A 95% confidence interval for the mean number of personal computers is<μ

According to the given information in this question We need to find 95% confidence interval

Answered: How many computers? In a simple random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You want to find out the average monthly rent for a studio apartment in Los Angeles. Out of a sample of n = 100 you find the sample average rent to be ?̅ = $1275. Assume you know the population standard deviation for studios’ monthly rent to be σ = $180. Develop a 90% confidence interval estimate of the population average monthly rent for studio apartments in Los Angeles
find a random sample size of 61 and a sample mean of 14.8 standard deviation 4.2. find 99%confidence interval what does E=? what is the confidence interval
The distribution of study times for first year students follows a Normal distribution with standard deviation σσ = 54 minutes. Suppose a sample of 487 students found that the mean study time for these students was x¯x¯= 173 minutes per week. Use this to find a 88.28% confidence interval to estimate the mean study time for all students. We are 88.28% confident that the mean study time for first year students is between minutes_____ and ____ minutes. What is the margin of error for your confidence interval?
A random sample of 500 observations yields x̅ =400 and s=50. What is the 95% confidence interval for the population mean?
You measure 38 backpacks' weights, and find they have a mean weight of 77 ounces. Assume the population standard deviation is 10.7 ounces. Based on this, what is the maximal margin of error associated with a 99% confidence interval for the true population mean backpack weight. Give your answer as a decimal, to two places H ounces
the population You measure 27 dogs' weights, and find they have a mean weight of 58 ounces. standard deviation is 7 ounces. Based on this, construct a 95% confidence interval for the true population mean dog weight. Give your answers as decimals, to two places - ounces Enter an integer or decimal number [more..]
You want to estimate the mean weight of quarters in circulation. A sample of 50 quarters has a mean weight of 5.658 grams and a standard deviation of 0.064 gram. Use a single value to estimate the mean weight of all quarters. Also, find the 95% confidence interval for the average weight of all quarters. grams. The estimate for the mean weight of all quarters is (Round to three decimal places as needed.) Find the 95% confidence interval for the mean weight of all quarters. grams<μ< grams (Round to three decimal places as needed.)
A researcher is interested in finding a 90% confidence interval for the mean number of times per day that college students text. The study included 149 students who averaged 34.2 texts per day. The standard deviation was 18.6 texts. Round to 3 decimals. b. With 90% confidence the population mean number of texts per day is between _______ and ________ texts a day.
You measure 48 textbooks' weights, and find they have a mean weight of 66 ounces. Assume the population standard deviation is 11.1 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weight.Give your answers as decimals, to two placesI am 95% confident that the mean weight of textbooks is between ________ and __________ ounces.
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
Determine the margin of error, ?m, for a 95% confidence interval when the sample size is ?=21n=21 and the sample standard deviation is ?=17.s=17.
Construct a 95% confidence interval of the population proportion using the given information. x=45, n=150 The lower bound is The upper bound is

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