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How many computers? In a simple random sample of 145 households, the sample mean number of personal computers was 2.38. Assume the population standard deviation is o=0.39 Part: 0 / 4 Part 1 of 4 (a) Construct an 80% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. An 80% confidence interval for the mean number of personal computers is

How many computers? In a simple random sample of 145 households, the sample mean number of personal computers was 2.38. Assume the population standard deviation is o=0.39 Part: 0 / 4 Part 1 of 4 (a) Construct an 80% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. An 80% confidence interval for the mean number of personal computers is

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
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Part 2 of 4 (b) If the sample size were 95 rather than 145, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) ▼ since (Choose one) ▼ in the sample size will (Choose one) vthe standard error. Part: 2 / 4 Part 3 of 4 (c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) ▼ since (Choose one) vin the confidence level will (Choose one) v the critical value Z2: Part: 3/4
Transcribed Image Text:Part 2 of 4 (b) If the sample size were 95 rather than 145, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) ▼ since (Choose one) ▼ in the sample size will (Choose one) vthe standard error. Part: 2 / 4 Part 3 of 4 (c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) ▼ since (Choose one) vin the confidence level will (Choose one) v the critical value Z2: Part: 3/4
How many computers? In a simple random sample of 145 households, the sample mean number of personal computers was 2.38. Assume the population do standard deviation is o=0.39. Part: 0 / 4 Part 1 of 4 (a) Construct an 80% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. An 80% confidence interval for the mean number of personal computers is
Transcribed Image Text:How many computers? In a simple random sample of 145 households, the sample mean number of personal computers was 2.38. Assume the population do standard deviation is o=0.39. Part: 0 / 4 Part 1 of 4 (a) Construct an 80% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. An 80% confidence interval for the mean number of personal computers is
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