How many clocks does it take for a change in Datain to be reflected on DataOut? module BitReverser ( input logic clk, input logic Rst, input logic [7:0] DataIn, output logic [7:0] Dataout ); assign Dataout [7] = DataIn[0]; assign DataOut [6] = DataIn[1]; assign Dataout [5] = DataIn[2]; assign Dataout [4] = DataIn[3]; assign Dataout [3] = DataIn[4]; assign Dataout [2] = DataIn[5]; assign DataOut[1] = DataIn[6]; assign Dataout [e] = DataIn [7]; endmodule
How many clocks does it take for a change in Datain to be reflected on DataOut? module BitReverser ( input logic clk, input logic Rst, input logic [7:0] DataIn, output logic [7:0] Dataout ); assign Dataout [7] = DataIn[0]; assign DataOut [6] = DataIn[1]; assign Dataout [5] = DataIn[2]; assign Dataout [4] = DataIn[3]; assign Dataout [3] = DataIn[4]; assign Dataout [2] = DataIn[5]; assign DataOut[1] = DataIn[6]; assign Dataout [e] = DataIn [7]; endmodule
Computer Networking: A Top-Down Approach (7th Edition)
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Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
![**Title: Understanding the Bit Reverser Module in Verilog**
**How many clocks does it take for a change in DataIn to be reflected on DataOut?**
```verilog
module BitReverser
(
input logic Clk,
input logic Rst,
input logic [7:0] DataIn,
output logic [7:0] DataOut
);
assign DataOut[7] = DataIn[0];
assign DataOut[6] = DataIn[1];
assign DataOut[5] = DataIn[2];
assign DataOut[4] = DataIn[3];
assign DataOut[3] = DataIn[4];
assign DataOut[2] = DataIn[5];
assign DataOut[1] = DataIn[6];
assign DataOut[0] = DataIn[7];
endmodule
```
**Explanation:**
The given Verilog code describes a module called `BitReverser`. It takes an 8-bit input `DataIn` and reverses the bits to produce an 8-bit output `DataOut`.
- `DataOut[7]` is assigned the value of `DataIn[0]`.
- `DataOut[6]` is assigned the value of `DataIn[1]`.
- This pattern continues until `DataOut[0]` is assigned the value of `DataIn[7]`.
This bit reversal is performed combinationally, meaning the output `DataOut` reflects changes in `DataIn` immediately without any clock delay.
**Pick one of the choices**
- ⭕ 0
- ⭕ 1
- ⭕ 4
- ⭕ 8
The correct choice is **0** since the change in `DataIn` is reflected immediately in `DataOut` without any clock cycles.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6d1ae07f-bdb5-47a8-9afa-ea5a04bdf9c8%2Ff9f77cbf-1a4b-42a3-b43f-53f0165c30da%2F67f7hkl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Understanding the Bit Reverser Module in Verilog**
**How many clocks does it take for a change in DataIn to be reflected on DataOut?**
```verilog
module BitReverser
(
input logic Clk,
input logic Rst,
input logic [7:0] DataIn,
output logic [7:0] DataOut
);
assign DataOut[7] = DataIn[0];
assign DataOut[6] = DataIn[1];
assign DataOut[5] = DataIn[2];
assign DataOut[4] = DataIn[3];
assign DataOut[3] = DataIn[4];
assign DataOut[2] = DataIn[5];
assign DataOut[1] = DataIn[6];
assign DataOut[0] = DataIn[7];
endmodule
```
**Explanation:**
The given Verilog code describes a module called `BitReverser`. It takes an 8-bit input `DataIn` and reverses the bits to produce an 8-bit output `DataOut`.
- `DataOut[7]` is assigned the value of `DataIn[0]`.
- `DataOut[6]` is assigned the value of `DataIn[1]`.
- This pattern continues until `DataOut[0]` is assigned the value of `DataIn[7]`.
This bit reversal is performed combinationally, meaning the output `DataOut` reflects changes in `DataIn` immediately without any clock delay.
**Pick one of the choices**
- ⭕ 0
- ⭕ 1
- ⭕ 4
- ⭕ 8
The correct choice is **0** since the change in `DataIn` is reflected immediately in `DataOut` without any clock cycles.
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