Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Title: Calculating Energy Release During Cooling of Steam**
**Question:**
How many calories are released when 58.4 g of steam at 144°C is cooled to -37.6°C?
**Explanation:**
This problem involves calculating the energy released when steam undergoes a temperature change, including phase transition from gas to liquid and from liquid to solid.
1. **Cooling of Steam to Water (144°C to 100°C):**
- Use the specific heat capacity of steam (2.09 cal/g°C) to find the energy released as steam cools to 100°C.
2. **Phase Change from Water Vapor to Liquid Water:**
- Use the heat of vaporization (540 cal/g) to determine the energy released during the steam's condensation into water at 100°C.
3. **Cooling of Water to Freezing Point (100°C to 0°C):**
- Use the specific heat capacity of water (1 cal/g°C) to calculate the energy released as water cools to 0°C.
4. **Phase Change from Liquid Water to Ice:**
- Use the heat of fusion (80 cal/g) to find the energy released during the freezing of water into ice.
5. **Cooling of Ice to -37.6°C:**
- Use the specific heat capacity of ice (0.5 cal/g°C) to calculate the energy released as ice cools from 0°C to -37.6°C.
The total energy released is the sum of all these energy changes. Calculating each step gives you the total calories released when 58.4 g of steam is cooled from 144°C to -37.6°C.
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