How many Cal need to be removed to condense 50.0 g of steam at 150.0 °C to water at 4.00 °C ? Use the conversions given below. First, the steam must first be cooled from 150.0 °C down to 100.0 °C, a change of i Second, the steam at 100.0 °C must be condensed to water at temperature Third, the water must be cooled from 100.0 °C to 4.00 °C, a change of i The answer is the addition of these three processes ( ( Р a. 0.504 cal/g °C f. 150.0 °C 1. 25.0 °C s. 4,795 y. -25.0 °C )(50.0 g)( )(50.0 g) )(50.0 g) Cal b. 79.7 cal/g g. 100.0 °C m. 37.0 °C t. 26,950 z. 5.00 c. 0.999 cal/g °C i. 50.0 °C h. 50.0 g n. 5.00 g u. 399.5 aa. 184.8 0. 647 v. 184.8 d. 539 cal/g j. 96.0 °C p. 33.0 w. 32,988 1,243 , there is no change in cal cal cal cal = e. 0.497 cal/g °C k. 4.0 °C r. 63.0 x. 25.0 °C

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5. How many Cal need to be removed to condense 50.0 g of steam at 150.0 oC to water at 4.00 oC ? ( answer is 33.0 CAL)

How many Cal need to be removed to condense 50.0 g of steam at 150.0 °C to water at 4.00 °C ? Use the
conversions given below.
First, the steam must first be cooled from 150.0 °C down to 100.0 °C, a change of i
Second, the steam at 100.0 °C must be condensed to water at
temperature
Third, the water must be cooled from 100.0 °C to 4.00 °C, a change of i
The answer is the addition of these three processes
(
(
Р
a. 0.504 cal/g °C
f. 150.0 °C
1. 25.0 °C
s. 4,795
y. -25.0 °C
)(50.0 g)(
)(50.0 g)
)(50.0 g)
Cal
b. 79.7 cal/g
g. 100.0 °C
m. 37.0 °C
t. 26,950
z. 5.00
c. 0.999 cal/g °C
i. 50.0 °C
h. 50.0 g
n. 5.00 g
u. 399.5
aa. 184.8
0. 647
v. 184.8
d. 539 cal/g
j. 96.0 °C
p. 33.0
w. 32,988
1,243
, there is no change in
cal
cal
cal
cal =
e. 0.497 cal/g °C
k. 4.0 °C
r. 63.0
x. 25.0 °C
Transcribed Image Text:How many Cal need to be removed to condense 50.0 g of steam at 150.0 °C to water at 4.00 °C ? Use the conversions given below. First, the steam must first be cooled from 150.0 °C down to 100.0 °C, a change of i Second, the steam at 100.0 °C must be condensed to water at temperature Third, the water must be cooled from 100.0 °C to 4.00 °C, a change of i The answer is the addition of these three processes ( ( Р a. 0.504 cal/g °C f. 150.0 °C 1. 25.0 °C s. 4,795 y. -25.0 °C )(50.0 g)( )(50.0 g) )(50.0 g) Cal b. 79.7 cal/g g. 100.0 °C m. 37.0 °C t. 26,950 z. 5.00 c. 0.999 cal/g °C i. 50.0 °C h. 50.0 g n. 5.00 g u. 399.5 aa. 184.8 0. 647 v. 184.8 d. 539 cal/g j. 96.0 °C p. 33.0 w. 32,988 1,243 , there is no change in cal cal cal cal = e. 0.497 cal/g °C k. 4.0 °C r. 63.0 x. 25.0 °C
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