How is the total [H3O*] of a 0.020 M aqueous solution of sulfuric acid, H2SO4, determined? O The [H30*] 0.020 M, then use K2 to solve for the additional [H3O*] from the second ionization O H2SO4 is polyprotic, so ignore Ka1, and use only Ka2 to solve for the [H3O*) O Make use of both Ka1 and Ka2 and solve the quadratic formula. O Since it is strong acid, the total [H3O*] is automatically equal to 0.020 M.

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How is the total [H3O*] of a 0.020 M aqueous solution of sulfuric acid, H2SO4, determined?
O The [H3O*] 0.020 M, then use K22 to solve for the additional [H30*] from the second ionization
%3D
O H2SO4 is polyprotic, so ignore Ka1, and use only Ka2 to solve for the [H3O*]
O Make use of both Ka1 and K22 and solve the quadratic formula.
O Since it is strong acid, the total [H30*] is automatically equal to 0.020 M.
Transcribed Image Text:How is the total [H3O*] of a 0.020 M aqueous solution of sulfuric acid, H2SO4, determined? O The [H3O*] 0.020 M, then use K22 to solve for the additional [H30*] from the second ionization %3D O H2SO4 is polyprotic, so ignore Ka1, and use only Ka2 to solve for the [H3O*] O Make use of both Ka1 and K22 and solve the quadratic formula. O Since it is strong acid, the total [H30*] is automatically equal to 0.020 M.
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