How is the temperature of an object related to the amount of heat it absorbs or gives off? We take the following definition: 1 calorie = amount of heat required to raise the temperature of 1 gram of water by 1.0°C (specifically from 14.5°C to 15.5°C) For example, if the temperature of 100 grams of water increases by 30°C. the water has absorbed 3,000 calories of heat, or Q = 3,000 cal, where Q denotes amount of heat, and cal stands for calories. Exercises: 1. How much heat is absorbed if the temperature of 50 grams of water increases by 15°C? 2. As 1 kg of water is heated from 28°C to 95°C, how much heat is absorbed by the water?

How is the temperature of an object related to the amount of heat it absorbs or gives off? We take the following definition: 1 calorie = amount of heat required to raise the temperature of 1 gram of water by 1.0°C (specifically from 14.5°C to 15.5°C) For example, if the temperature of 100 grams of water increases by 30°C. the water has absorbed 3,000 calories of heat, or Q = 3,000 cal, where Q denotes amount of heat, and cal stands for calories. Exercises: 1. How much heat is absorbed if the temperature of 50 grams of water increases by 15°C? 2. As 1 kg of water is heated from 28°C to 95°C, how much heat is absorbed by the water?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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