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how is the 0.071s^2 + 0.389s + 0.727 was computed through regression? can someone explain?

how is the 0.071s^2 + 0.389s + 0.727 was computed through regression? can someone explain?

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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how is the 0.071s^2 + 0.389s + 0.727 was computed through regression? can someone explain?

Now, substituting v = 20, 40, 60, 80 and 100 respectively into the obtained equation then, 20 40 60 80 100 S 5.56 11.11 16.67 22.22 27.78 d 5.1 13.7 27.2 44.2 66.4 Step 2 use the regression capabilities of a graphing utility to find the model of the form d (s) = as? + bs + c then, d (s) = 0.071s² + 0. 389s + 0. 727 d(s) Now, calculating the minimum value of T then substitute d (s) into the equation T (s) = + 55 T (s) = (0.071s2² + 0. 389s + 0. 727) + 3 5.5 T (s) = 0.071s + 0. 389 + 6.227
Transcribed Image Text:Now, substituting v = 20, 40, 60, 80 and 100 respectively into the obtained equation then, 20 40 60 80 100 S 5.56 11.11 16.67 22.22 27.78 d 5.1 13.7 27.2 44.2 66.4 Step 2 use the regression capabilities of a graphing utility to find the model of the form d (s) = as? + bs + c then, d (s) = 0.071s² + 0. 389s + 0. 727 d(s) Now, calculating the minimum value of T then substitute d (s) into the equation T (s) = + 55 T (s) = (0.071s2² + 0. 389s + 0. 727) + 3 5.5 T (s) = 0.071s + 0. 389 + 6.227
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