I solved this question by first finding the vant hoff coefficient i Then plugging it in the freezing depression formula Could you please tell me if my work is correct how I solved this letknowSelect the solution with the lowest freezing temperatureaqueousa) 0.2m HNO3 → HNO₂ → H²+NO₂ i=22x0.2=0.4melowest b) 01m CH₂2 →i=1 ⇒ 1x0.1 = 0.1c) 0.3m C₂H₂ →i=11x0.3 = 0.3d) o. lm BaCl₂ → BaCl₂ → Ba²+ + 2(1¯e) o.l CuSOy → CuSoy Cu²+ + 50i=3 ⇒ 3×0.1=0.3i= 2 = 2x0.1 = 0.2

The freezing point of a solution is a colligative property, which means it depends on the number of…

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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I solved this question by first finding the vant hoff coefficient i Then plugging it in the freezing depression formula Could you please tell me if my work is correct

how I solved this let
know
Select the solution with the lowest freezing temperature
aqueous
a) 0.2m HNO3 → HNO₂ → H²+NO₂ i=22x0.2=0.4
me
lowest b) 01m CH₂2 →i=1 ⇒ 1x0.1 = 0.1
c) 0.3m C₂H₂ →i=11x0.3 = 0.3
d) o. lm BaCl₂ → BaCl₂ → Ba²+ + 2(1¯
e) o.l CuSOy → CuSoy Cu²+ + 50
i=3 ⇒ 3×0.1=0.3
i= 2 = 2x0.1 = 0.2

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