How i can do this to one loop The code :- #include int main(void) { double arr[50][5]; int count = 0; int rows = 0; while(1) { // if 5 items are entered then if(count == 5) { // reset count count = 0; // increment row number rows = rows+1; // take input from user to stop or continue printf("If you want to stop please enter 0, to continue enter 1 : "); int temp; scanf("%d",&temp); if(temp == 0) break; } else { if(count == 0) printf("Enter 5 items to store : "); // take input for next number scanf("%lf",&arr[rows][count]); count = count + 1; } } printf("Entered items are : \n"); // print all the entered data for(int i=0;i

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How i can do this to one loop The code :- #include int main(void) { double arr[50][5]; int count = 0; int rows = 0; while(1) { // if 5 items are entered then if(count == 5) { // reset count count = 0; // increment row number rows = rows+1; // take input from user to stop or continue printf("If you want to stop please enter 0, to continue enter 1 : "); int temp; scanf("%d",&temp); if(temp == 0) break; } else { if(count == 0) printf("Enter 5 items to store : "); // take input for next number scanf("%lf",&arr[rows][count]); count = count + 1; } } printf("Entered items are : \n"); // print all the entered data for(int i=0;i
niophnjopjpk.cpp - Dev-C++5.11
oject Execute Tools AStyle Window Help
TDM-GCC 4.9.2 32-bit
[*] ohiophnjopjpk.cpp
please enter 0, to continue enter 1 : “);
printf("If you
int temp;
scanf("Xd",&temp);
if(temp = 0)
break;
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to
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24
else {
if(count == 0)
printf("Enter 5 items to store : ");
// take input for next number
scanf ("%1f",&arr[rows][count]);
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count
count + 1;
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printf("Entered items are : \n"),
35
print all the entered data
for (int i=0;i<rows;i++) {
for (int j=03j<5;j++)
printf("%0.21f
printf("\n");
36
37 E
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arr[i][j]);
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42
return 0;
ces dh Compile Log Debug Find Results Close
Message
In function 'int main()':
iba\Desktop\ohiophnjopjpk.cpp
Transcribed Image Text:niophnjopjpk.cpp - Dev-C++5.11 oject Execute Tools AStyle Window Help TDM-GCC 4.9.2 32-bit [*] ohiophnjopjpk.cpp please enter 0, to continue enter 1 : “); printf("If you int temp; scanf("Xd",&temp); if(temp = 0) break; 17 to 18 19 20 21 22 23 24 else { if(count == 0) printf("Enter 5 items to store : "); // take input for next number scanf ("%1f",&arr[rows][count]); 25 26 27 28 29 count count + 1; 30 31 32 33 34 printf("Entered items are : \n"), 35 print all the entered data for (int i=0;i<rows;i++) { for (int j=03j<5;j++) printf("%0.21f printf("\n"); 36 37 E 38 arr[i][j]); 39 40 41 42 return 0; ces dh Compile Log Debug Find Results Close Message In function 'int main()': iba\Desktop\ohiophnjopjpk.cpp
ophnjopipk.cpp- Dev-C++ 5.11
ect
Execute
Tools AStyle Window Help
TDM-GCC 4.9.2 3
] ohiophnjopjpk.cpp
#include <stdio.h>
BA int main(void) {
double arr[50][5];
int count = 05
int rows = 05
while (1) {
// if 5 items are entered then
if(count == 5) {
// resetCount
count = 0;
/increment row number
1日
2.
4
rows = rowS+1;
/ take tnput from user to stop or contirue
printf("If you want to stop please enter 0, to continue enter 1 : ");
int temp;
8
scanf ("%d", &temp);
if(temp == 0)
break;
9
2
3
4 A
else
if (count == 0)
printf("Enter 5 items to store : ");
6
s di Compile Log
Debug S Find Results 3 Close
Message
\Desktop\ohiophnjopjpk.cpp
In function 'int main():
Transcribed Image Text:ophnjopipk.cpp- Dev-C++ 5.11 ect Execute Tools AStyle Window Help TDM-GCC 4.9.2 3 ] ohiophnjopjpk.cpp #include <stdio.h> BA int main(void) { double arr[50][5]; int count = 05 int rows = 05 while (1) { // if 5 items are entered then if(count == 5) { // resetCount count = 0; /increment row number 1日 2. 4 rows = rowS+1; / take tnput from user to stop or contirue printf("If you want to stop please enter 0, to continue enter 1 : "); int temp; 8 scanf ("%d", &temp); if(temp == 0) break; 9 2 3 4 A else if (count == 0) printf("Enter 5 items to store : "); 6 s di Compile Log Debug S Find Results 3 Close Message \Desktop\ohiophnjopjpk.cpp In function 'int main():
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