Help please ---**Question:**How high will a winch motor with a power of 483 Watts lift an 18 kg crate straight up against gravity in 29 seconds?**Your Answer:**---*Explanation for Educational Purposes:*To determine the height the crate will be lifted, you can use the formula for power:\[ \text{Power (P)} = \frac{\text{Work (W)}}{\text{Time (t)}} \]Where Work (W) is defined as:\[ W = \text{Force (F)} \times \text{Distance (d)} \]The force here is equal to the weight of the crate, which is mass (m) times gravity (g):\[ F = m \times g \]Substituting these into the power formula gives:\[ P = \frac{m \times g \times d}{t} \]Rearrange this to solve for distance (d):\[ d = \frac{P \times t}{m \times g} \]Inserting the values: - Power (P) = 483 Watts- Time (t) = 29 seconds- Mass (m) = 18 kg- Gravity (g) = 9.81 m/s² (approximately)\[ d = \frac{483 \times 29}{18 \times 9.81} \]Calculate this value to find how high the crate will be lifted.

Answered: How high will a winch motor with a…

How high will a winch motor with a POWER of 483 Watts lift a 18 kg crate straight up against gravity in 29 seconds. Your Answer:

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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